There are two choices for each child: overweight (o) or underweight (u). So if the first child is o the next can be o or u. If the first is u the second can be o or u. This gives four possibilities. Here the first child is the letter noted first and the second is the one listed second:
OO
OU
UO
UU
There are 4 outcomes and if each is equally likely then the probability of each is 1/4. Thus the probability of UU is 1/4
The probability of one underweight and one over weight is 1/2 because in two of the outcomes listed above there is one O and one U (namely OU and UO). Since there are 4 outcomes the probability is 2/4 = 1/2
Answer: Rectangle
Reasoning: 4 straight sides, 2 pairs of sides of equal length.
Answer:
Step-by-step explanation:
Let
c -----> the additional amount (in dollars) David will spend
we know that
The word " at most" in this context means "less than or equal to"
The amount David has spent plus possible additional amounts he will spend must be less than or equal to $39
so
The inequality that represent this situation is
solve for c
subtract 22 both sides
The maximum amount he could spend is $17
Answer:
its 4
Step-by-step explanation:
a 1 = 3 , a n = a n - 1 + 2
because if you aply this to the shapes that you see at problem 21 you will see that it meaches them
