To find f'(3) (f prime of 3), you must find f' first. f' is the derivative of the function f(x).
Finding the derivative of f(x) = 2x⁴ requires the use of the power rule.
The power rule for derivatives is ![\frac{d}{dx} [x^{n} ] =nx^{n-1}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bx%5E%7Bn%7D%20%5D%20%3Dnx%5E%7Bn-1%7D)
. In other words, you bring the exponent forward and multiply it by the coefficient of the term, and then you subtract 1 from the original exponent.
f'(x) = 
(2x⁴)
f'(x) = 2(4)x³
f'(x) = 8x³
Now, to find f'(3), plug 3 into your derivative.
f'(3) = 8(3)³
f'(3) = 216
<h3>Answer:</h3>
f'(3) = 216
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To solve this one-step equation you:
1. Substract 9 in both sides of the equation:
In this step is the mistake as Sara gets as result -4x=29 and the corret result of substract 9 in both sides of the equation is 5x=20.
2. Divide both sides of the equation into 5:
Then, the answer that Sara should found for the equation is x=4
Perhaps you meant <span>(a^3+14a^2+33a-20) / (a+4), for division by (a+4).
Do you know synthetic division? If so, that'd be a great way to accomplish this division. Assume that (a+4) is a factor of </span>a^3+14a^2+33a-20; then assume that -4 is the corresponding root of a^3+14a^2+33a-20.
Perform synth. div. If there is no remainder, then you'll know that (a+4) is a factor and will also have the quoitient.
-4 / 1 14 33 -20
___ -4_-40 28___________
1 10 -7 8
Here the remainder is not zero; it's 8. However, we now know that the quotient is 1a^2 + 10a - 7 with a remainder of 8.
Answer:
x = 4.8
Step-by-step explanation:
Since quadrilateral JKLM and PQRS are similar toe ach other, therefore the ratio of their corresponding sides are equal.
Thus:
QP/KJ = PS/JM
Substitute
8/5 = x/3
Cross multiply
5*x = 3*8
5x = 24
x = 24/5
x = 4.8
