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ra1l [238]
2 years ago
15

Please answer the following;

Mathematics
1 answer:
34kurt2 years ago
6 0

The Surface area of the cube will be 433.5 square feet.  Then the correct option is C.

<h3>What is a surface area of a cube?</h3>

Suppose that: The side length of the considered cube is L units. Then, we get:

Surface area of that cube = 6L² square units.

Bella is wrapping a cube shape box that measures 8.5 inches along each side.

The edge length of the cube is 8.5 meters.

Then the Surface area of the cube will be

Surface area = 6 x 8.5²

Surface area = 6 x 72.25

Surface area = 433.5 square feet

The Surface area of the cube will be 433.5 square feet.

Then the correct option is C.

More about the surface area of the cube link is given below.

brainly.com/question/13789496

#SPJ1

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Solve the inequality for x. 12x &gt;9(2x-3)-15 show each step to the solution
monitta

12x >9(2x-3)-15

distribute

12x> 18x-27-15

combine like terms

12x>18x -42

subtract 18x from each side

12x -18x >18x-18x-42

-6x>-42

divide by -6 which will flip the inequality

-6x/-6<-42/-6

x<7


7 0
3 years ago
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What does s equal?pls help me plsss.
Archy [21]

Answer:

s< -7/11

Step-by-step explanation:

6 0
3 years ago
Use a Maclaurin series to obtain the Maclaurin series for the given function.
Rama09 [41]

Answer:

14x cos(\frac{1}{15}x^{2})=14 \sum _{k=0} ^{\infty} \frac{(-1)^{k}x^{4k+1}}{(2k)!15^{2k}}

Step-by-step explanation:

In order to find this Maclaurin series, we can start by using a known Maclaurin series and modify it according to our function. A pretty regular Maclaurin series is the cos series, where:

cos(x)=\sum _{k=0} ^{\infty} \frac{(-1)^{k}x^{2k}}{(2k)!}

So all we need to do is include the additional modifications to the series, for example, the angle of our current function is: \frac{1}{15}x^{2} so for

cos(\frac{1}{15}x^{2})

the modified series will look like this:

cos(\frac{1}{15}x^{2})=\sum _{k=0} ^{\infty} \frac{(-1)^{k}(\frac{1}{15}x^{2})^{2k}}{(2k)!}

So we can use some algebra to simplify the series:

cos(\frac{1}{15}x^{2})=\sum _{k=0} ^{\infty} \frac{(-1)^{k}(\frac{1}{15^{2k}}x^{4k})}{(2k)!}

which can be rewritten like this:

cos(\frac{1}{15}x^{2})=\sum _{k=0} ^{\infty} \frac{(-1)^{k}x^{4k}}{(2k)!15^{2k}}

So finally, we can multiply a 14x to the series so we get:

14xcos(\frac{1}{15}x^{2})=14x\sum _{k=0} ^{\infty} \frac{(-1)^{k}x^{4k}}{(2k)!15^{2k}}

We can input the x into the series by using power rules so we get:

14xcos(\frac{1}{15}x^{2})=14\sum _{k=0} ^{\infty} \frac{(-1)^{k}x^{4k+1}}{(2k)!15^{2k}}

And that will be our answer.

3 0
3 years ago
Mercury: 3.3022*10^23 kg earth: 5.9722*10^24 kg
pshichka [43]

Answer:

The average mass of the inner planets is = 2.9531925 x 1024 kg.

5 0
3 years ago
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I Need Help!! Answer Please!!
Crank

Answer:

50 degrees

Step-by-step explanation:

all inside angles in every triangle can be added up to equal 180 degrees.

this is a right angle, so one has to be 90 degrees

on the bottom right it's marked 140 degrees on the outside, in order to find the inside angle, you need to subtract 140 from 180, which gives you 40 degrees

180-90=90

90-40=50

so the answer is 50

if that's not clear enough leave a comment, hope this helps!

6 0
4 years ago
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