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3 years ago

10

For babysitting, Nicole charges a flat fee of $3, plus $5 per hour. Write an equation for the cost, C, after h hours of babysitt

ing help?

1 answer:

galben [10]3 years ago

5 0

Answer:

c = 3 + 5h

Step-by-step explanation:

Flat fee is constant

and $5 per hour is variable

c = 3 + 5h

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Need the answer for this angle measures<br> A? <br> B (4x-16)<br> C (5x+7)

marta [7]

Is it an isosceles triangle

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4 years ago

Distances in space are measured in light-years. The distance from Earth to a star is 6.8 × 1013 kilometers. What is the distance

aalyn [17]

6.8 x 10^13 = 68,000,000,000,000
9.46 x10 ^12 = 9,460,000,000,000

6.8 x 10^13 * 1 light year / 9.46 x 10^12 = 7.188 light years.

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3 years ago

-8 -8x + 10 + 6x = 19

hram777 [196]

Answer:

x = -8.5

Step-by-step explanation:

Let's rearrange the question to find x :)

-8x + 6x + 10 - 8 = 19

-2x + 2 = 19

-2 -2

-2x = 17

/-2 /-2

x = -8.5

4 0

3 years ago

It is estimated that 0.54 percent of the callers to the Customer Service department of Dell Inc. will receive a busy signal. Wha

stira [4]

Using the binomial distribution, it is found that there is a 0.8295 = 82.95% probability that at least 5 received a busy signal.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

0.54% of the calls receive a busy signal, hence p = 0.0054.

A sample of 1300 callers is taken, hence n = 1300.

The probability that at least 5 received a busy signal is given by:

$P(X \geq 5) = 1 - P(X < 5)$

In which:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4).

Then:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{1300,0}.(0.0054)^{0}.(0.9946)^{1300} = 0.0009$

$P(X = 1) = C_{1300,1}.(0.0054)^{1}.(0.9946)^{1299} = 0.0062$

$P(X = 2) = C_{1300,2}.(0.0054)^{2}.(0.9946)^{1298} = 0.0218$

$P(X = 3) = C_{1300,3}.(0.0054)^{3}.(0.9946)^{1297} = 0.0513$

$P(X = 4) = C_{1300,4}.(0.0054)^{4}.(0.9946)^{1296} = 0.0903$

Then:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0009 + 0.0062 + 0.0218 + 0.0513 + 0.0903 = 0.1705.

$P(X \geq 5) = 1 - P(X < 5) = 1 - 0.1705 = 0.8295$

0.8295 = 82.95% probability that at least 5 received a busy signal.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

6 0

2 years ago

Which of the following statements best describes the value of the expression 6x + 7 when x = 5?

Tanzania [10]

Answer:

? is there a option?

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers