Question

What are the points of discontinuity y=(x-5)/x^2-6x+5?

Answer 1

$y = \frac{x - 5}{x^{2} - 6x + 5}$
$y = \frac{x - 5}{(x - 1)(x - 5)}$
$y = \frac{1}{x - 1}$

x - 1 = 0
  + 1  + 1
     x = 1