2 years ago

What are the points of discontinuity y=(x-5)/x^2-6x+5?

Mathematics

1 answer:

ollegr [7]2 years ago

3 0

$y = \frac{x - 5}{x^{2} - 6x + 5}$
$y = \frac{x - 5}{(x - 1)(x - 5)}$
$y = \frac{1}{x - 1}$

x - 1 = 0
+ 1 + 1
x = 1

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