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svetoff [14.1K]
2 years ago
5

What are the points of discontinuity y=(x-5)/x^2-6x+5?

Mathematics
1 answer:
ollegr [7]2 years ago
3 0
y = \frac{x - 5}{x^{2} - 6x + 5}
y = \frac{x - 5}{(x - 1)(x - 5)}
y = \frac{1}{x - 1}

x - 1 = 0
  + 1  + 1
     x = 1
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Answer:

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Step-by-step explanation:

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2 years ago
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Step-by-step explanation:

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