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2 years ago

Pls Help Construction Quiz

Mathematics

1 answer:

pochemuha2 years ago

7 0

Answer:

Angle Bisector

the arc was constructed were the two lines met making it to form an angle

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If m< 1 = 10x + 4 and m <2 = 5x-4, find m< 2

BartSMP [9]

Answer:

m<2 = 56°

Step-by-step explanation:

m<1 and m<2 are supplementary angles and sum = 180

m<1 + m< 2 = 180

If m< 1 = 10x + 4 and m <2 = 5x-4, find m< 2

10x + 4 + 5x - 4 = 180

15x = 180

x = 12

m<2 = 5(12) -4 = 56

Answer

m<2 = 56°

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3 years ago

Which undefined geometric term is described as an infinite set of points that has length but not width?

aleksandr82 [10.1K]

The answer is a line.

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3 years ago

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Question 1<br> The Federal Student Aid office provides about how much money in aid each year?

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More then 120 billion grant

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3 years ago

Evaluate the integral using the indicated trigonometric substitution. (use c for the constant of integration.) x^3 / sqrt x^2 +

slava [35]

$\displaystyle\int\frac{x^3}{\sqrt{x^2+49}}\,\mathrm dx$

Taking $x=7\tan\theta$ gives $\mathrm dx=7\sec^2\theta\,\mathrm d\theta$ , so that the integral becomes

$\displaystyle\int\frac{(7\tan\theta)^3}{\sqrt{(7\tan\theta)^2+49}}(7\sec^2\theta)\,\mathrm d\theta$
$=\displaystyle7^4\int\frac{\tan^3\theta\sec^3\theta}{\sqrt{49\tan^2\theta+49}}\,\mathrm d\theta$
$=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sqrt{\tan^2\theta+1}}\,\mathrm d\theta$
$=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sqrt{\sec^2\theta}}\,\mathrm d\theta$
$=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{|\sec\theta|}\,\mathrm d\theta$

When $\sec\theta>0$ , we have

$=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sec\theta}\,\mathrm d\theta$
$=\displaystyle7^3\int\tan^3\theta\sec^2\theta\,\mathrm d\theta$

and from here we can substitute $u=\tan\theta$ to proceed from here.

Quick note: When we set $x=7\tan\theta$ , we are implicitly enforcing $-\dfrac\pi2$ just so that the substitution can be undone later via $\theta=\tan^{-1}\dfrac x7$ . But note that over this domain, we automatically guarantee that $\sec\theta>0$ , so the absolute value bars can be dropped immediately.

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3 years ago

An algebra test contains 38 problems. Some of the problems are worth 2 points each. The rest of the questions are worth 3 points

Naily [24]

Let 'x' be the problems worth 2 points.

Let 'y' be the problems worth 3 points.

Since, there are 38 total problems.

So, $x+y =38$ (equation 1)