Answer:
See below
Step-by-step explanation:
Here is how to start....you didn't include the equations in question, so I do not know what the answer may be
solve for x
y-10 = 5 x^2 divide thru by 5
(y-10)/5 = x^2 'sqrt' both sides
± sqrt( (y-10) / 5 = x change x's and y's
± sqrt ((x-10)/5) = y
Answer:
Second answer
Step-by-step explanation:
first answer: 4 negative numbers multiplied = 2 postive numbers multipled = 1 positive number
second answer: 3 negative numbers multiplied = 1 positive number multiplied by 1 negative number = 1 negative number
third answer: Negative and positive numbers multiplied by zero = 0
fourth answer: 2 negative numbers multiplied by 2 positive numbers = 1 positive number multiplied by 1 positive number = positive number.
Answer:
Step-by-step explanation:
(9+(15*15))+7=241
Answer:
x + 2y ≤ 100 and x + 3y ≤ 400
Maximum profit = 6x + 5y.
Step-by-step explanation:
Let there be x number of small dishes and y number of large dishes to maximize the profit.
So, total profit is P = 6x + 5y .......... (1)
Now, the small dish uses 1 cup of sauce and 1 cup of cheese and the large dish uses 2 cups of sauce and 3 cups of cheese.
So, as per given conditions,
x + 2y ≤ 100 ........ (1) and
x + 3y ≤ 400 .......... (2)
Therefore, those are the constraints for the problem. (Answer)
Answer:
unit rate is 2
Step-by-step explanation:
Notice that if we multiply both '1' and '3' in 1/3 by 2, we get:
4/6 : 2/6,
which reduces to 4/2, or 2, which is the desired unit rate.