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RideAnS [48]
2 years ago
8

A patient has an inherited defect in the liver enzyme fructose 1,6-bisphosphatase and this results in an abnormally high levels

of lactate in the blood plasma. explain this observation.
Biology
1 answer:
DedPeter [7]2 years ago
6 0

If the live enzyme fructose 1,6- bisphosphatase defect is occured and this results in an abnormally high levels of lactate in the blood plasme this will result into the lactate will accumulate into the blood.

What is the work of fructose 1,6-biphosphatase enzyme?

In the liver, gluconeogenesis converts lactate to glucose. If FBPase-1 is defective, lactate cannot enter the gluconeogenic pathway in hepatocytes, building up in the blood.

A crucial enzyme in gluconeogenesis is fructose 1,6-bisphosphatase (FBPase). It is a possible target for drugs used to treat type II diabetes. Additionally, the protein is linked to a rare genetic metabolic disorder, and certain cancer cells lack the activity of the enzyme FBPase, which encourages glycolysis and aids in the Warburg effect.

To learn more about fructose 1,6-biphosphatase enzyme click the given link

brainly.com/question/13717824

#SPJ4

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Therefore, in the newly discovered Biologica terificia species of snail, if the haploid state (n) of their gametes is 4, then their diploid (2n) somatic cells must be 4 × 2 = 8.

The question specifies the chromosomal number at the G1 phase of Interphase. At this stage, the cell is preparing to undergo division by increasing in size and duplicating its organnelles but not yet its genetic material which is not until the next phase called S-phase. Hence, the chromosome number of somatic cells remain 8 at the G1 phase.

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