Given:
The solution decreased by 
ounces every hour for 5 hours.
Remaining solution at the end of the experiment = 
ounces.
To find:
The initial amount of solution.
Solution:
Let the initial amount of the solution be x.
The solution decreased by ounces every hour for 5 hours.
Total decreased amount 
Initial amount = Remining amount + Decreased amount of solution.
Therefore, the initial amount of solution is 18 ounces.
The answer is c. Anaphase I separates homologous chromosomes and anaphase II separates sister chromatids into daughter cells.
Meiosis is a cell division which results in the reduction of chromosome number by half (from diploid to haploid) in daughter cells. It consists of meiosis I and meiosis II.
In anaphase I, the sister chromatids separate from each other to the opposite sides of the cells. In meiosis I there are 46 chromosomes in duplicates which are present as pairs of sister chromatids. When comes to separation, homologous chromosomes separates only, but not sister chromatids. Homologous chromosomes are present only in meiosis I.
In anaphase II, since the cell is haploid, there are 23 chromosomes in duplicates, which are present as sister chromatids. So, in this phase, sister chromatids are those who separates.
Answer:
The suitable option will be - B
B) Phosphate and ADP form to make ATP which binds to the myosin head and causes cross-bridge to detach.
Explanation:
Until step 11, skeletal muscle has already done cross-bridge and power stroke. ADP is released just after the power stroke. After that phosphate and ADP form a new ATP which gets bound to the myosin head.
Then at step 11, cross-bridge is released as a new ATP is bound to myosin head.
So, we can say that option B is correct.
A. in DNA can result in dysfunctional protein productiona. Your answer is Point mutation
