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natita [175]
2 years ago
5

Step-by-step answer?

Mathematics
2 answers:
yawa3891 [41]2 years ago
7 0

hi

a ( b +c) =  a*b +a*c

here a = -3  

        b = -4x

        c = +5

so :  

-3 ( -4x +5)  =  -3*-4x + -3* 5  

                   =  -12x + (-15)

                  = -12x -15

as I cannot add  -12x and  -15   ( they are two differents sort of figures )

so it's done

Alinara [238K]2 years ago
4 0

Answer:

12x - 15

Step-by-step explanation:

What you need to do for this is -3 · -4x + -3 · 5 = 12x+(-15). Which simplifies to 12x - 15.

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Which of the following shows that △ABD≅△CBD, when y=5?
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The correct option is;

∠ADB ≅ ∠CDB, \overline {BD} ≅ \overline {BD} and \overline {AD} ≅ \overline {CD}. So ΔABD ≅ ΔCDB by SAS

Step-by-step explanation:

The given parameters are;

The polygon given = Quadrilateral

The diagonal of the quadrilateral = BD

The length of the side AD = (2×y + 5) units

The length of the side CD = (y + 10) units

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The given measure of ∠CBD = 35°

When y = 5, we have by substituting the value of y into the equations representing the dimensions of the quadrilateral ABCD;

The length of the side AD = 2 × y + 5 = 2×5 + 5 = 15 units

∴ The length of the side AD = 15 units

The length of the side CD = (y + 10) units = (5 + 10) units = 15 units

∴ The length of the side CD = 15 units

The measure of ∠ABD = (2 × y + 25)° = (2 × 5 + 25)° = 35°

The measure of ∠ABD = 35°

Therefore;

∠ADB ≅ ∠CDB by substitution

\overline {BD} ≅ \overline {BD} by reflexive property

\overline {AD} ≅ \overline {CD} by substitution

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(10 pts) A four-lane freeway (two lanes in each direction) is located on rolling terrain and has 12-ft lanes, no lateral obstruc
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Answer:

309

Step-by-step explanation:

To determine the estimated free-flow speed

FFS = 75.4 -f_{LW}-f_{LC} - 3.22 TRD^{0.84}

From the table "Adjustment for lane width," which corresponds to a lane width of 12 feet. As a result, f_{LW} equals 0 mi/h.

Take the meaning from the table "Adjustment for right-shoulder lateral clearance," which corresponds to 6 feet of right shoulder lateral clearance and two lanes in one direction.

The f_{LC} = 0 mi/h

FFS = 75.4 -0-0-3.22 ( \dfrac{5}{6})^{0.84}

= 72.64 \ mi/h

\simeq  73 \ mi/h

Determine the peak-hour factor

PHF = \dfrac{V}{V_{15}\times 4} \\ \\ =\dfrac{1800}{700\times 4}\\ \\ = 0.6429

Now, Find the heavy-vehicle adjustment factor.

v_P = \dfrac{V}{PHF\times N \times f_{HV}\times f_P} --- (1)

Take the value for the 15-minute passenger car equivalent flow rate from the table "LOS requirements for freeway segments" for the FFS and LOS C conditions. The free-flow speed is estimated to be 73 miles per hour

v_p = 1735+ \dfrac{73-70}{75-70}(1775-1735)

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Think about for familiar users the value of f_p = 1.00

Replace all of the values obtained in (1)

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Calculate the percentage of trucks and buses in the flow of traffic stream.

f_{HV} = \dfrac{1}{1+P_{\tau}(E_{\tau}-1) + P_R(E_R-1)}

Take the values from the table "Passenger car equivalent for extended highway segments" referring to trucks and buses and rolling terrains for passenger car equivalent for trucks and buses and recreational vehicles. As a result, E_T has a value of 2.5 and E_R has a value of 2.0.

Since P_R is zero and there is no recreational vehicle.

Then;

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Finally, to estimate the maximum number of large trucks and buses; we have:

= V\times P_T = 1800 \times 0.1719

Maximum number of large trucks and buses = 309

4 0
3 years ago
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