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Lapatulllka [165]
4 years ago
12

Suppose that a local area network requires eight letters for user names. Lower- and uppercase letters are considered the same. H

ow many user names are possible for the local area network?
Mathematics
2 answers:
Sergio [31]4 years ago
5 0

Answer:

208,827,064,576 user names

Step-by-step explanation:

There are "8" places for each letter of the alphabet.

Since upper and lowercase are same and let's assume repetition is possible, we can say that each "placeholder" can hold 26 letters.

According to counting rule, we have to multiply the number of possibilities in each "place". That would be:

26*26*26*26*26*26*26*26 = 208,827,064,576 user names

There are over 208 billion user names possible(!!!)

Yuri [45]4 years ago
3 0

Answer:62990928000 usernames

Step-by-step explanation:

Eight letters are required for username from a possible 26 alphabets

Upper and lower case are considered the same, so we have 26alphabets to choose from.

In combining the letters to form the username, the order of the letters are important.

In thus case, we use permutation

nPr = n!/(n-r)!r!

n = 26, r = 8

26P8 = 26! / (18!)8!

= 62990928000 usernames

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Which number is between 8.270 and 8.280
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8.275

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Answer:

$393.75

$2,446.88

Step-by-step explanation:

Let's take this problem one step at a time. First let's compute for the total price after the sales tax has been added.

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4,500 x 0.0875 = $393.75

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