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bagirrra123 [75]
2 years ago
7

How would I solve for x on this question

Mathematics
2 answers:
SIZIF [17.4K]2 years ago
8 0
Distributive Property
gregori [183]2 years ago
7 0

Answer:

use your distributive properties and combine the two equations and just use pemdas.

Step-by-step explanation:

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Is the distance jumped a constant or variable
Advocard [28]
It’s a variable because when you justo I can’t stay the same every time it changes
8 0
3 years ago
A ladder 20 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at a rate of 2
alukav5142 [94]

Answer:

0.17 °/s

Step-by-step explanation:

Since the ladder is leaning against the wall and has a length, L and is at a distance, D from the wall. If θ is the angle between the ladder and the wall, then sinθ = D/L.

We differentiate the above expression with respect to time to have

dsinθ/dt = d(D/L)/dt

cosθdθ/dt = (1/L)dD/dt

dθ/dt = (1/Lcosθ)dD/dt where dD/dt = rate at which the ladder is being pulled away from the wall = 2 ft/s and dθ/dt = rate at which angle between wall and ladder is increasing.

We now find dθ/dt when D = 16 ft, dD/dt = + 2 ft/s, and L = 20 ft

We know from trigonometric ratios, sin²θ + cos²θ = 1. So, cosθ = √(1 - sin²θ) = √[1 - (D/L)²]

dθ/dt = (1/Lcosθ)dD/dt

dθ/dt = (1/L√[1 - (D/L)²])dD/dt

dθ/dt = (1/√[L² - D²])dD/dt

Substituting the values of the variables, we have

dθ/dt = (1/√[20² - 16²]) 2 ft/s

dθ/dt = (1/√[400 - 256]) 2 ft/s

dθ/dt = (1/√144) 2 ft/s

dθ/dt = (1/12) 2 ft/s

dθ/dt = 1/6 °/s

dθ/dt = 0.17 °/s

8 0
3 years ago
PLEASE HELP ASAP
Andrei [34K]

Answer: 35 the digits both together = 8

Reverse it and add 2.

53+2 =55

55- 35 = 20

The required answer is 35 :)

Step-by-step explanation:

7 0
2 years ago
What is the correct order of these numbers ... 5/6, 12/13, 0.8
Ratling [72]
0.8 4/6 12/13 I think
6 0
3 years ago
Read 2 more answers
Help with this question?? :c
mojhsa [17]
The answer is 1.52 to your question.
5 0
3 years ago
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