Answer:
<u>First figure:</u> 
<u>Second figure:</u> 
<u>Third figure:</u>
- Height= q
- Side length = r
<u>Fourth figure: </u> 
Explanation:
<u></u>
<u>A. First figure:</u>
<u>1. Formula:</u>

<u>2. Data:</u>
<u>3. Substitute in the formula and compute:</u>

<u>B. Second figure</u>
<u>1. Formula: </u>

<u>2. Data:</u>
<u>3. Substitute and compute:</u>

<u></u>
<u>C) Third figure</u>
a) The<em> height </em>is the segment that goes vertically upward from the center of the <em>base</em> to the apex of the pyramid, i.e.<u> </u><u>q </u>.
The apex is the point where the three leaned edges intersect each other.
b) The side length is the measure of the edge of the base, i.e.<u> r </u><u> </u>.
When the base of the pyramid is a square the four edges of the base have the same side length.
<u>D) Fourth figure</u>
<u>1. Formula</u>
The volume of a square pyramide is one third the product of the area of the base (B) and the height H).

<u>2. Data: </u>
- side length of the base: 11 cm
<u>3. Calculations</u>
a) <u>Calculate the area of the base</u>.
The base is a square of side length equal to 11 cm:

b) <u>Volume of the pyramid</u>:

Y= 0.26x+4.4*10^-4
Y= 0.26x+4.4*10,000
Y=0.26x+44,000
I'm not sure if you were only trying to simplify the problem, but I hope this helped
Answer:
The reactant that acts as an acid, by contributing an H⁺ ion to create H3O+ in the chemical equation is C₆H₅OH.
Step-by-step explanation:
According to Brønstend-Lowry, an acid is a substance that transfer a proton (hydrogen cation, H⁺) to a base, forming a base conjugate for the first and an acid conjugate for the second.
From the following reaction:
C₆H₅OH(aq) + H₂O(l) → C₆H₅O⁻(aq) + H₃O⁺(aq)
We have that the C₆H₅OH transfer a proton to the water to form its conjugate base C₆H₅O⁻ and the conjugate acid of water H₃O⁺. Hence, the C₆H₅OH is the acid and the water is the base.
Therefore, the reactant that acts as an acid, by contributing an H⁺ ion to create H3O+ in the chemical equation is C₆H₅OH.
I hope it helps you!
Answer:
Option B.
{–9 + i√225 / 24, –9 – i√225 / 24}
Step-by-step explanation:
12a² + 9a + 7 = 0
Using formula method, the solutions to the equation can be obtained as follow:
Coefficient of a² (a) = 12
Coefficient of a (b) = 9
Constant (c) = 7
a = –b ±√(b² – 4ac) / 2a
a = –9 ±√(9² – 4 × 12 × 7) / 2 × 12
a = –9 ±√(81 – 336) / 24
a = –9 ±√(– 225) / 24
Recall
–225 = –1 × 225
Thus,
–9 ±√(– 225) / 24 = –9 ±√(–1 × 225)/24
Recall
√(–1 × 225) = √–1 × √225 = i√225
Thus,
–9 ±√(–1 × 225)/24 = –9 ± i√225/24
Therefore,
a = –9 ± i√225/24
a = –9 + i√225 / 24 or –9 – i√225 / 24
Therefore, the solutions to the equation are:
{–9 + i√225 / 24, –9 – i√225 / 24}
Answer:
-2 7/12
Step-by-step explanation:
Let x represent the unknown number.
x + (-5 2/3) = -8 1/4
Adding 5 2/3 to both sides of the equation tells us ...
x = 5 2/3 -8 1/4 = -2 7/12
The other number is -2 7/12.
_____
The difference can be found as ...
-(8 1/4 -5 2/3) = -(8 3/12 -5 8/12) = -((8 -5) +(3/12 -8/12)) = -(3 -5/12)
= -(2 7/12)