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Arisa [49]
1 year ago
10

R(6 1/2)=5(6 1/2) - 3.5

Mathematics
1 answer:
Airida [17]1 year ago
3 0

The value of r in the equation r(61/2)=5(61/2)-3.5 is 4.88.

Given an equation r(61/2)=5(61/2)-3.5.

We are required to find the value of r in the equation.

Equation is like a relationship between two or more variable that are expressed in equal to form. The equation of two variables look like ax+by=c. It may be a linear equation, quadratic equation, cubic equation and many more depending on the powers of the variable present in that equation.

In our equation the variable is r.

The equation is given as:

r(61/2)=5(61/2)-3.5

r(61/2)=305/2-3.5

r(61/2)=(305-7)/2

r(61/2)=298/2

r=(298*2)/(2*61)

r=596/122

r=4.88

Hence the value of r in the equation r(61/2)=5(61/2)-3.5 is 4.88.

Learn more about equation at brainly.com/question/2972832

#SPJ1

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(3 points) Blades of grass Suppose that the heights of blades of grass are Normally distributed and independent, with each heigh
NemiM [27]

The final answer is:

a) P( Y < 42.5 )  = 0.8541

b) P( 39.5 < Y < 40.5 ) = 0.1670.

What is the normal distribution?

A continuous probability distribution for a real-valued random variable in statistics is known as a normal distribution or Gaussian distribution.

If x follows a normal distribution with mean μ and standard deviation σ then the distribution of

\sum_{i =1}^{n}x_{i}  follows an approximately normal distribution with a mean n\mu and standard deviation \sqrt{n }\sigma

let x be the height of blades of grass

x follows normal distribution with mean = μ = 4 and standard deviation = σ = 0.75.

Y = x1 + x2 +...........+x10

Y = \sum_{i =1}^{10}x_{i}

Distribution of Y is normal with,

Mean = \mu _{y}=10*4 = 40 and standard deviation = \sigma _{y}=\sqrt{10}*0.75 = 2.3717

a)

P( Y < 42.5 )

Using normal distribution formmula,

f(x)= {\frac{1}{\sigma\sqrt{2\pi}}}e^{- {\frac {1}{2}} (\frac {x-\mu}{\sigma})^2}

=NORMDIST( x, mean, SD , 1 )      

=NORMDIST(42.5, 40, 2.3717, 1 )

=0.8541

P( Y < 42.5 )  = 0.8541

b)

P( 39.5 < Y < 40.5 ) = P( Y < 40.5 ) - P( Y < 39.5 )

Using normal distribution formmula,

f(x)= {\frac{1}{\sigma\sqrt{2\pi}}}e^{- {\frac {1}{2}} (\frac {x-\mu}{\sigma})^2}

P( Y < 40.5 )  =NORMDIST(40.5, 40, 2.3717, 1 ) = 0.5835

P( Y < 39.5 ) = NORMDIST(39.5, 40, 2.3717, 1 ) = 0.4165

P( 39.5 < Y < 40.5 ) = 0.5835 - 0.4165  = 0.1670

P( 39.5 < Y < 40.5 ) = 0.1670

Hence, the final answer is:

a) P( Y < 42.5 )  = 0.8541

b) P( 39.5 < Y < 40.5 ) = 0.1670.

To learn more about the normal distribution visit,

brainly.com/question/4079902

#SPJ4

5 0
1 year ago
Please Help And EXPLAIN And ANSWER!
frutty [35]

Answer: Area is 426

Step-by-step explanation: Do 15 x 26 which is 390 to find out the rectangle part, and the area for a triangle is 1/2 (b x h) so 9 x 8 is 72 and then divide by 2 is 36 so 390 + 36 is 426

4 0
2 years ago
Read 2 more answers
A polynomial that has 4 turning points is multiplied by another polynomial that has 9 zeros. What is the minimum degree of the n
pickupchik [31]
For a given degree of the polynomial, the number of turning points is given by n-1, where n is the degree of the polynomial. A polynomial that has x number of zeros is a polynomial of degree x. Thus the polynomial that has 9 zeros and 4 turning points, is a polynomial of degree 9.
5 0
3 years ago
Helpppppp pleaseeeee ):
fenix001 [56]

Answer:

Smily face=5 lightning=8

Step-by-step explanation:

5+5=10 8x3=24      24+10=34

8x5=40              5x8=40

3 0
2 years ago
If the federal budget for 2007 was 2.8 trillion dollars, how much money did the government spend per second? Please help!
diamong [38]

Solution:

we are given that

The federal budget for 2007 was 2.8 trillion dollars.

we have been asked to find

how much money did the government spend per second?

First we will find the number of seconds in one year

Number of seconds in 1 year=365*24*60*60=31536000 Seconds

Now we will dive the amount by the total number of seconds, we get

\frac{2,800,000,000,000}{31536000} =88787.41755 dollar

Hence the government is spending approximately 88787 dollars per second.

5 0
3 years ago
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