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horsena [70]
2 years ago
5

Which function has a vertex at the origin?

Mathematics
1 answer:
dlinn [17]2 years ago
6 0

Answer:

  (d)  f(x) = -x²

Step-by-step explanation:

For the vertex of the quadratic function to be at the origin, both the x-term and the constant must be zero. That is, the function must be of the form ...

  f(x) = a(x -h)² +k . . . . . . . . . . vertex form; vertex at (h, k)

  f(x) = a(x -0)² +0 = ax² . . . . . vertex at the origin, (h, k) = (0, 0)

Of the offered answer choices, the only one with a vertex at the origin is ...

  f(x) = -x² . . . . . a=-1

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Answer:

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Step-by-step explanation:

The equation of a quadratic function in vertex form is given by:

f(x)=a(x-h)^2+k

Where (h,k) is the vertex.

It was given in the question that the vertex of the parabola is (-1,4).

When we substitute the vertex into the formula we get:

f(x)=a(x+1)^2+4

The parabola also passes through (4,19) hence it must satisfy its equation.

19=a(4+1)^2+4

19-4=a(5)^2

15=25a

We divide both sides by 25 to get:

a=\frac{15}{25}= \frac{3}{5}

Hence the quadratic function is:

f(x)=\frac{3}{5}(x+1)^2+4

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