The answer is B. please mark me as brainlyest.
Answer:
rate boat = 15 mph
rate current = 5 mph
explanation:
d = r * t
t = d/r
240 / (r_boat + current) = 12 Multiply both sides by r_boat + r_current.
240 = 12(r_boat + current)
240/ (r_boat - current) = 24 Multiply both sides by r_boat - r_current
240 = 24*(r_boat - current)
Since the distances are the same in both equations, you can equate the right side of each.
12 (r_boat + current) = 24(r_boat - current) Divide by 12
r_boat + current = 2 (r_boat - current) Remove the brackets.
r_boat + current = 2*r_boat - 2* current add 2 currents to both sides
r_boat + 3currents = 2*r_boat Subtract r_boat both sides
3 currents = r_boat.
240 = 12*(r_boat + current. Divide by 12
20 = r_boat + current Put 3 currents in for r_boat
20 = 3currents + 1 current Combine
20 = 4 currents Divide by 4
5 = current
The rate of the current = 5 miles / hour
3 currents = r_boat
3*5 = rate_boat
15 = rate of the boat
Answer:
the answer is 1
Step-by-step explanation:
the bottom says 6 and the other top says 7 so the only right answer is 1
Answer:
![\large\boxed{x=1\ and\ y=\dfrac{1}{2}}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7Bx%3D1%5C%20and%5C%20y%3D%5Cdfrac%7B1%7D%7B2%7D%7D)
Step-by-step explanation:
Look at the picture.
Answer:
![a. \ p=0.38\\\\b. \ \ H_o:p=0.38\\\ \ \ \ \\H_A:p\neq 0.38](https://tex.z-dn.net/?f=a.%20%5C%20p%3D0.38%5C%5C%5C%5Cb.%20%5C%20%5C%20H_o%3Ap%3D0.38%5C%5C%5C%20%5C%20%5C%20%5C%20%5C%5CH_A%3Ap%5Cneq%200.38)
Step-by-step explanation:
a. Let, p be the parameter being tested. From the sample, 38% would erase all of their personal information.
-we know that the value of probabilities are in the range [0,1]:
-Given that 38% is the true value of the claim can be symbolically expressed as p=0.5
b. The null hypothesis usually represents the true value parameter under study.
-As stated above, the true value of the parameter is 38%;
-Hence, the null hypothesis is ![H_o:p=0.38](https://tex.z-dn.net/?f=H_o%3Ap%3D0.38)
#Alternative hypothesis is the control value, given the value of the parameter p=0.38, the alternative hypothesis is that p has a different value other than 0.39:
![H_A:p\neq 0.38](https://tex.z-dn.net/?f=H_A%3Ap%5Cneq%200.38)