The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant =
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.
Yes, because |-13+2| is |-11| And |10+1| is |11|. Since it’s the absolute value, which is the distance it is from 0, they both are 11. So 11=11
Answer:
hope this helps
Step-by-step explanation:
Let a , b , c are three sides of a triangle
a : b : c = 3 : 4 : 5
a = 3x ,
b = 4x ,
c = 5x
a² = 9x²
b² = 16x²,
c² = 25x².
c² = a² + b²
by the pythagorean theorem,
a , b , c forms a right angled Triangle.
I believe the answer is (3,4)