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Lelechka [254]
3 years ago
15

HELP HURRYYYY If you spin the spinner below 150 times, which of the following outcomes are reasonable? Select all that apply. A)

Lands on blue 60 times B) Lands on red 120 times C) Lands on yellow 90 times D) Lands on yellow 44 times

Mathematics
2 answers:
dalvyx [7]3 years ago
8 0

Answer \

c land on yellow 90 time

Ratling [72]3 years ago
7 0

Answer:

all but B & D

Step-by-step explanation:

the sum of all data=314

314-120=194

164-44=150

I WAS WRONG THE ANSWERS WERE A AND D: DONT BELIEVE ME VIEW COMMENTS BELOW

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Radioactive Decay:
Vadim26 [7]

The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.

<u>Step-by-step explanation:</u>

All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half life period of the reaction = 46 days

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{46days}\\\\k=0.01506days^{-1}

The formula used to calculate the time period for a first order reaction follows:

t=\frac{2.303}{k}\log \frac{a}{(a-x)}

where,

k = rate constant = 0.01506days^{-1}

t = time period = ? days

a = initial concentration of the reactant = 12.6 g

a - x = concentration of reactant left after time 't' = 1 g

Putting values in above equation, we get:

t=\frac{2.303}{0.01506days^{-1}}\log \frac{12.6g}{1g}\\\\t=168.27days

Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.

7 0
3 years ago
Does |-13 + 2| equal to |10 + 1|
lesya [120]
Yes, because |-13+2| is |-11| And |10+1| is |11|. Since it’s the absolute value, which is the distance it is from 0, they both are 11. So 11=11
8 0
4 years ago
If the sides of a triangle are in the ratio 3:4:5, prove that it is<br>right-angled triangle​
lyudmila [28]

Answer:

hope this helps

Step-by-step explanation:

Let a , b , c are three sides of a triangle

a : b : c = 3 : 4 : 5

a = 3x ,

b = 4x ,

c = 5x

a² = 9x²

b² = 16x²,

c² = 25x².

c² = a² + b²

by the pythagorean theorem,

a , b , c forms a right angled Triangle.

6 0
3 years ago
Read 2 more answers
Simplify.<br><br> If x = 4, evaluate -x<br><br> A: -8<br> B: 4<br> C: 0<br> D: -4
Blizzard [7]
D obviously because -4 is -x
6 0
3 years ago
Read 2 more answers
Help help help help help help help help
guapka [62]

I believe the answer is (3,4)

8 0
3 years ago
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