Given: ∠ DEF
To construct: ∠TSZ ≅ ∠DEF
Construction: Consider the attachment
Step-01: Draw a line XY and choose a point S on it as a vertex of the required angle. Further marks point T such that DE = ST
Step-02: Take an arc AB from point E in ∠DEF of any length and draw at point S which cuts at point P on XY line.
Step-03: Take another arc of length AB from point B in ∠DEF and draw from point P which cuts to the previous arc at Q.
Step-04: Now, join the point SQ and extend up to Z such that EF = SZ
Hence, ∠ TSZ will be the required congruent constructed angle to∠DEF
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<h3>Answer : y = ⅚x - 3</h3>════════════════════
<h3>Known</h3>x1 = 6
y1 = 2
x2 = (-6)
y2 = (-8)
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<h3>Question</h3>Equation of the line (y = mx + c)
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<h3>Way to do</h3>#First, you find the gradient (m)
#Now use the formula of equation of the line
y - y1 = m(x - x1)
y - 2 = ⅚(x - 6)
y - 2 = ⅚x - 5
y = ⅚x - 5+2
y = ⅚x - 3
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