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astra-53 [7]
1 year ago
10

3y+z=am-4y look for y

Mathematics
1 answer:
LenKa [72]1 year ago
3 0

The value of y is am-z/7

<h3>How to calculate the value of y ?</h3>

The expression is given as follows

3y +z= am-4y

The first step is to collect the like terms in both sides, this way the numbers that both have y as their coefficient will be on the same side

3y + 4y= am-z

y(3+4)= am -z

7y= am-z

Divide both sides by the coefficient of y which is 7

7y/7= am-z/7

y= am-z/7

Hence the value of y in the expression is am-z/7

Read more on expression here

brainly.com/question/13591446?referrer=searchResults

#SPJ1

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She swam 12 hours in 3 weeks.
5 0
3 years ago
If P is the orthocenter of △ABC, AB = 13, BF = 9,and FC = 5.6, find each measure &amp; the perimeter of triangle ABC.
harina [27]

Answer:

Perimeter = 38.6

Step-by-step explanation:

Given

A\ B = 13

B\ F = 9

F\ C = 5.6

Required

Calculate the perimeter of A B C

To calculate the perimeter of A B C, we sum up the sides of the triangle

i.e.

Perimeter = A B + B\ C + A\ C

AB is given in the question already.

So, we need to calculate B F and F C

To solve for BF, we consider triangle B F C

Using Pythagoras Theorem, we have:

B\ C^2 = B\ F^2 + F\ C^2

Substitute values for BF and FC;

B\ C^2 = 9^2 + 5.6^2

B\ C^2 = 81 + 31.36

B\ C^2 = 112.36

B\ C^2= \sqrt{112.36

B\ C = 10.6

Next, we calculate A C.

To calculate A C, we need to calculate A F, considering triangle B F A

Using Pythagoras Theorem, we have:

A\ B^2 = B\ F^2 + A\ F^2

Substitute values for B F and A B;

13^2 = 9^2 + A\ F^2

169= 81 + A\ F^2

A\ F^2 = 169 - 81

A\ F^2 = 88

A\ F = \sqrt{88

A\ F = 9.4

Since F lies on line A C:

A\ C = A\ F + F\ C

A\ C = 9.4 + 5.6

A\ C = 15.0

Recall that:

Perimeter = A\ B + B\ C + A\ C

Perimeter = 13 + 10.6 + 15.0

Perimeter = 38.6

<em>Hence, the perimeter is 38.6</em>

3 0
3 years ago
Nadia plans to paint her jewelry box. The box is shaped like a rectangular prism with the dimensions
Pachacha [2.7K]

Answer:

132\ in^{2} is closest to the total surface area of the box

Step-by-step explanation:

we know that

The surface area of the box is equal to

SA=2B+PH

where

B is the area of the base

P is the perimeter of the base

H is the height of the box

we have

L=7\frac{3}{4}\ in=\frac{7*4+3}{4}=\frac{31}{4}\ in

W=3\frac{1}{4}\ in=\frac{3*4+1}{4}=\frac{13}{4}\ in

H=3\frac{7}{8}\ in=\frac{3*8+7}{8}=\frac{31}{8}\ in

<em>Find the area of the base B</em>

B=LW

B=(\frac{31}{4})(\frac{13}{4})=\frac{403}{16}\ in^{2}

<em>Find the perimeter of the base P</em>

P=2(L+W)

P=2(\frac{31}{4}+\frac{13}{4}))

P=2(\frac{44}{4})=22\ in

<em>Find the surface area</em>

SA=2(\frac{403}{16})+22(\frac{31}{8})

SA=(\frac{403}{8})+(\frac{682}{8})

SA=\frac{1,085}{8}=135.625\ in^{2}

6 0
3 years ago
Grade 7th math anybody know the answer
TiliK225 [7]

Our answer is attached.

I hope it helped.

=)

4 0
2 years ago
What are the x-intercepts of the quadratic function?
maw [93]
To find the x intercept set y = 0

x^2 + x  - 2 =0 

(x+2)(x-1) = 0

x = -2 , x = 1


8 0
3 years ago
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