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dedylja [7]
3 years ago
12

East Middle's football team was positioned on the 50 yard line. After a penalty is called, the football team is pushed back 5 ya

rds. If East Middle's football team is charged with the same penalty 3 plays in a row, on what yard line is the football team positioned?
A. 65 yard line
B. 35 yard line
C. 25 yard line
D. 15 yard line
Mathematics
2 answers:
Rufina [12.5K]3 years ago
3 0

Answer:

The answer would be the 35 yard line.

Step-by-step explanation: This is because if they get a 5 yard penalty 3 times, that would be a total of 15 yards lost. So, you would do 50-15, getting 35, so boom, 35 yard line :)

deff fn [24]3 years ago
3 0
B. the 35 yard line
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3 years ago
Please solve all with explanation
garri49 [273]

Answer:

1. \frac{x^2}{y^8}

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Step-by-step explanation:

1.

(\frac{x^{-3}y^4}{x^{-2}})^{-2}\\({x^{-3+2}y^4})^{-2}\\({x^{-1}y^4})^{-2}({x^{-1*-2}y^{4*-2})= \frac{x^2}{y^8}

2. a)

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\frac{3}{4}x + \frac{5}{6} = 5x -\frac{125}{3} \\\frac{5}{6} + \frac{125}{3} = 5x - \frac{3}{4}x\\\frac{5+250}{6} = \frac{20x -3x}{4}\\\frac{255}{6} = \frac{17x}{4}\\x = 10

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7 0
2 years ago
Find zeroes and multiplicity for y=(2x +3)(x -1)^2
muminat

Answer:

zeros : -3/2 , multiplicity = 1

1 , multiplicity = 2

Step-by-step explanation:

y=(2x +3)(x -1)^2

To find zeros we set each factor =0  and solve for x

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divide by 2 on both sides

x= -3/2

The exponent of (2x+3) is 1 so multiplicity =1

Now we set (x-1)^2 =0

take square root on both sides

x-1 =0

add 1 on both sides

x=1

For (x-1)^2  the exponent is 2

So multiplicity = 2


7 0
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