East Middle's football team was positioned on the 50 yard line. After a penalty is called, the football team is pushed back 5 ya
2 answers:
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There are 330 different ways for choosing a dozen donuts from the 4 varieties at a donut shop. (at least one donut of every variety must be selected)
<h3>How to calculate the number of ways to select items?</h3>There are 'r' items from 'n' different varieties (repetition allowed). Then, the number of ways to select items is given by
The number of ways =
Where the combination is calculated as
It is given that there are 4 varieties of donuts in a shop. I.e., n = 4
Number of donuts to be selected r = 12 (one dozen)
And also given that at least one donut of every variety has to be selected.
Since there are 4 varieties, at least one from each of these means the count is 4.
So, the remaining number of donuts to be selected is 12 - 4 = 8.
So, r becomes 8 i.e., r = 8
On substituting,
the number of ways of selecting the remaining 8 donuts =
⇒
⇒
⇒
⇒ 330
Therefore, there are 330 different ways for choosing a dozen donuts from the 4 varieties at a donut shop.
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The equation which represents the height of the books is
A mathematical equation is a formula that uses the equals sign to represent the equality of two expressions. An equation between two sums of monomials of degree 0 or 1 is known as a linear equation.
The books are stacked one above the other and each book is inches thick.
So to calculate the total height of the stack we have to multiply the number of books in the stack with the thickness of each book.
The total thickness is represented in the from of a function as
s(b) and the thickness of each book is inches
total height=
Therefore the required equation is .
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Answer:
Dimensions: 150 m x 150 m
Area: 22,500m²
Step-by-step explanation:
Given information:
- Rectangular field
- Total amount of fencing = 600m
- All 4 sides of the field need to be fenced
Let = width of the field
Let = length of the field
Create two equations from the given information:
<u>Area of field</u>:
<u>Perimeter of fence</u>:
Rearrange the equation for the perimeter of the fence to make y the subject:
Substitute this into the equation for Area:
To find the value of x that will make the area a <em>maximum</em>, <u>differentiate</u> A with respect to x:
Set it to zero and solve for x:
Substitute the found value of x into the original equation for the perimeter and solve for y:
Therefore, the dimensions that will give Tanya the maximum area are:
150 m x 150 m
The maximum area is: