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frutty [35]
3 years ago
10

fill in the missing number in this newspaper report: houses cost 150.000 a year ago.they now cost is ?. this is a 25% increase w

hat is the cost now. ​
Mathematics
2 answers:
svet-max [94.6K]3 years ago
8 0

Answer: 187500

Step-by-step explanation:

Interest= principal ×rate×time/100

Let interest be I

Principal be P

Rate be r

Time be t

So we have

I=p×r×t/100

P in the question is 150000

T is 1year

R is 25%

Substitute for the values

I=150000×1×25/100

Interest= 37500

To know the exact cost now

Add the interest to the principal cost

Exact value=interest +principal

Exact value =37500+150000

Exact value=187500

The cost of the house now is=187500

Wittaler [7]3 years ago
6 0
The answer is 187500
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A climatologist wants to determine the thickness of a glacier with a surface area of about 2 km². He selected 10 locations at ra
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8 0
3 years ago
345 ft/min = ___________ ft/h
Pavlova-9 [17]

the rate given is 345 ft/min

this means within 1 min distance is - 345 ft

we have to convert this speed to ft/h

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so if 60 minutes equals 1 hour

1 minute is equal to - 1/60 hr

so the distance within 1 minute is - 345 ft

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8 0
3 years ago
Read 2 more answers
A randomized controlled study was designed to test whether regular drinking of cranberry juice can prevent the recurrence of uri
Kamila [148]

Answer:

1. The chi-squared statistic = 10.36

The degrees of freedom = 17

The p-value for the test = 0.89

2. The range of the p-value from the Chi squared table = 0.75 < p-value < 0.90

Step-by-step explanation:

1. The Chi squared test is given as follows;

\chi ^{2} = \sum \dfrac{\left (Observed - Expected  \right )^{2}}{Expected  }

Therefore,

                              UTI   No UTI    %     Total

Cranberry juice       8           42      84     50

Lactobacillus          19          30       61     49

Control                    18          30      60    50

The chi-squared statistic is given as follows;

\chi ^{2} = \dfrac{\left (8- 18\right )^{2}}{18} +  \dfrac{\left (42 - 30\right )^{2}}{30} = 10.36

The chi-squared statistic = 10.36

The degrees of freedom, df = 18 - 1 = 17 since the all of the expected count have a minimum value of 18

With the aid of the calculator we find the p value as p as follows;

p = 0.9 - \dfrac{10.36 - 10.085}{12.972 - 10.085} \times (0.9 - 0.75)

The p-value for the test = 0.89  

2. The range of the p-value from the Chi squared table is given as follows;

0.75 < p-value < 0.90.

5 0
3 years ago
Drake must practice the
dybincka [34]
I’m pretty sure you do need to subtract 30-8.
8 0
3 years ago
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