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emmainna [20.7K]
2 years ago
15

a printer's accessory list includes a maintenance kit with a variety of replaceable parts you should install after 100,000 pages

. which printer technology does it probably use?
Computers and Technology
1 answer:
Triss [41]2 years ago
4 0

Answer:

Laser printer

Explanation:

This is a guess based on experience, but laser printers have rollers, drums, and other various parts that need periodic replacement.

See page 87 of https://www.laserpros.com/img/manuals/hp-manuals/hp-lj-4100-manual.pdf for an example.

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Ayuda no encuentro la información de estas tres preguntas:
Morgarella [4.7K]

Answer:

Sorry i don't know.........!!!!!!!!!!

Explanation:

3 0
3 years ago
Explain how to implement two stacks in one array A[1..n] in such a way that neither stack overflows unless the total number elem
algol [13]

Answer:

Check explanation

Explanation:

Two stacks can make use of one array by utilizing various stack pointers that begins from different ends of an array. Looking at the array A[1...n], the first stack will drive elements that starts from position 1 as well as to move its' pointer to n.

The Second stack will begin at the n position and motion its' pointer to 1. The best likely divide is to offer each stack a half of an array. whenever any of two stacks transverse the half-point, an overflow can happen but for that overall number of elements, it must be n

5 0
3 years ago
Write code that does the following: opens an output file with the filename number_list.txt, uses a loop to write the numbers 1 t
Lady_Fox [76]

Answer:

# create the file

filename = "Testfile.txt"

# for writing, we create the output file:

outPutfile = open(filename, "w")

# Writing numbers from 1-100

for item in range(1,101):

 outPutfile.write((str)(item))

outPutfile.close()

# printing the contents to verify it worked correctly

infile = open(filename, "r") #note the "r" indicates the mode

fileContents = infile.read()

infile.close()

print(fileContents)

Explanation:

  • Define the working file fileName = TestFile
  • Create the output file for writting outPutfile = open(filename, "w")
  • Use a for loop to write numbers from 1-100 to the file outPutfile.write((str)(item))
  • Close the file outPutfile.close()
  • You may open the file read its content and print the contents to verify it worked correctly
8 0
3 years ago
1,2,3,4,5,6,7,8,9,10 – Best case - Sorted in ascending order
Pepsi [2]

Using the knowledge in computational language in python it is possible to write a code that from a random number draw creates an order of increasing numbers

<h3>Writting the code in python:</h3>

<em>def shellSort(array, n):</em>

<em>    # Rearrange elements at each n/2, n/4, n/8, ... intervals</em>

<em>    interval = n // 2</em>

<em>    while interval > 0:</em>

<em>        for i in range(interval, n):</em>

<em>            temp = array[i]</em>

<em>            j = i</em>

<em>            while j >= interval and array[j - interval] > temp:</em>

<em>                array[j] = array[j - interval]</em>

<em>                j -= interval</em>

<em>            array[j] = temp</em>

<em>        interval //= 2</em>

<em>data = [10,9,8,7,6,5,4,3,2,1]</em>

<em>size = len(data)</em>

<em>shellSort(data, size)</em>

<em>print('Sorted Array in Ascending Order:')</em>

<em>print(data)</em>

See more about python at brainly.com/question/18502436

#SPJ1

5 0
2 years ago
Assume that source elements of length k are mapped in some uniform fashion into a target elements of length p. If each digit can
lukranit [14]

Answer And explanation

a)

r^k has 1/r^k probability guess the correct source

b)

Each element in r^p  is mapped by r^k / r^p . There are r^k^-^p  So there are  r^k^-^p -1 elements.

number of target elements = r^k^-^p

number of source elements = r^k^-^p -1

probability = r^k^-^p -1 /r^k

c) Probability of the correct target element

1/r^p

6 0
3 years ago
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