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Gnom [1K]
3 years ago
7

Political parties to address the interest of civil society​

Computers and Technology
1 answer:
jeka943 years ago
7 0

Answer:

I DON'T KNOW THE ANSWER SO SORRY

Explanation:

BUT THANKS FOR THE POINTS

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Consider a set of mobile computing clients in a certain town who each
poizon [28]

Answer: answer given in the explanation

Explanation:

We have n clients and k-base stations, say each client has to be connected to a base station that is located at a distance say 'r'. now the base stations doesn't have allocation for more than L clients.

To begin, let us produce a network which consists of edges and vertex

Network (N) = (V,E)

where V = [S, cl-l, - - - -  cl-n, bs-l - - - - - - bs-k, t]

given that cl-l, - - - - - cl-n represents nodes for the clients

also we have that bs-l, - - - - - bs-k represents the nodes for base station

Also

E = [ (s, cl-i), (cl-i,bs-j), (bs-j,t)]

(s, cl-i) = have capacity for all cl-i (clients)

(cl-i,bs-j) = have capacity for all cl-i  clients & bs-j (stations)

⇒ using Fond Fulkorson algorithm we  find the max flow in N

⇒ connecting cl-i clients to  bs-j stations

      like (cl-i, bs-j) = 1

   if f(cl-i, bs-j)  = 0

⇒ say any connection were to produce a valid flow, then

if cl-i (clients) connected                f(s,cl-i) = 1 (o otherwise)

if cl-i (clients) connected  to bs-j(stations)   f(cl-i,bs-j) = 1 (o otherwise)

   f(bs-j,t) = no of clients  (cl-i)  connected to bs-j

⇒ on each node, the max flow value (f) is longer than the no of clients that can be connected.

⇒ create the connection between the client and base station i.e. cl-l to base bs-j iff    f(cl-i, bs-j) = 1

⇒ when considering the capacity, we see that any client cannot directly connect to the base stations, and also the base stations cannot handle more than L clients, that is because the load allocated to the base statsion is L.

from this, we say f is the max no of clients (cl-i) that can be connected if we find the max flow, we can thus connect the client to the base stations easily.

cheers i hope this helps

5 0
3 years ago
Round Robin Algorithm
Reil [10]

Answer:

Please check the attachment.

Explanation:

avg turnaround time = (38+7+42+33+18)/5= 27.6

avg waiting timee = (33+5+28+23+17)/5= 21.2

And its D, A C in Gantt chart at last and exit time are 33, 38 and 42 mentioned as last three in Gantt chart.

7 0
3 years ago
Explain the working system of computer systems with examples​
geniusboy [140]

,I don't know you all about computer

8 0
3 years ago
Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards
ozzi

Answer:

The missing part of the code is:

for (i = 0; i < courseGrades.length; ++i) {

           System.out.print(courseGrades[i]+" ");         }

       System.out.println();

       for (i = courseGrades.length-1; i >=0 ; --i) {

           System.out.print(courseGrades[i]+" ");         }

       System.out.println();

Explanation:

This iterates through the array

for (i = 0; i < courseGrades.length; ++i) {

This prints each element of the array followed by a space

           System.out.print(courseGrades[i]+" ");         }

This prints a newline at the end of the loop

       System.out.println();

This iterates through the array in reverse

       for (i = courseGrades.length-1; i >=0 ; --i) {

This prints each element of the array (reversed) followed by a space

           System.out.print(courseGrades[i]+" ");         }

This prints a newline at the end of the loop

       System.out.println();

6 0
3 years ago
When a project is saved, the new file name appears on the ____ tab?
BartSMP [9]
It appears on Document window tab
7 0
3 years ago
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