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2 years ago

Consider the expression 1/3 bwh

Mathematics

1 answer:

ANEK [815]2 years ago

4 0

The entire expression is the product of 4 factors and in this context , 1/3 is a coefficient

<h3>How to complete the statements?</h3>

The expression is given as:

1/3bwh

Where the factors of the expression are:

1/3, b, w and h

And also 1/3 is a coefficient (because 1/3 is a number)

So, the complete statement is:

the entire expression is the product of 4 factors and in this context , 1/3 is a coefficient

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What is the perimeter of the following figure?

PSYCHO15rus [73]

Answer:

13.4 x 2 = 26.8

12.5

HYPOTENUSE:

10^2 + 12.5^2 = 256.25

Square root of 256.25 = around 16

which would equal 256

16 is your hypotenuse.

26.8 + 12.5 + 16 = 55.3 is your perimeter

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3 years ago

What is 12×6 equal to?

Natasha2012 [34]

12 times 6 is 72.

We find this by adding 12+12+12+12+12+12
24+24+24
48+24
72
This is another way to get to our answer.

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4 years ago

Read 2 more answers

The speed that a tsunami can travel is modeled by the equation , where s is the speed in kilometers per hour and d is the averag

dusya [7]

The approximate depth of water for a tsunami traveling at 200 kilometers per hour, given the equation S=356√d, where S is the speed in kilometers per hour and d is the average depth of the water in kilometers, is 0.32 km. Hence, option A is the correct choice.

To solve for the average depth of water, when the water is traveling at 200 kilometers per hour, we substitute speed S = 200, in the relation S = 356√d.

This will be solved in the following way:

S = 356√d,

or, 200 = 356√d {Substituting S = 200},

or, 200/356 = (356√d)/356 {Dividing both sides by 356},

or, √d = 0.5618 {Simplifying},

or, d = 0.32 kilometers.

Therefore, the approximate depth of water for a tsunami traveling at 200 kilometers per hour, given the equation S=356√d, where S is the speed in kilometers per hour and d is the average depth of the water in kilometers, is 0.32 km. Hence, option A is the correct choice.

The provided question is incomplete.

The complete question is:

"The speed that a tsunami can travel is modeled by the equation S=356√d, where S is the speed in kilometers per hour and d is the average depth of the water in kilometers. What is the approximate depth of water for a tsunami traveling at 200 kilometers per hour?

A. 0.32 km

B. 0.75 km

C. 1.12 km

D. 3.17 km"

Learn more about speed and depth relation at

brainly.com/question/2456082

#SPJ4

5 0

2 years ago

What is the area of a circle with a circumference of 4π^2 ?

skelet666 [1.2K]

$\bf \textit{circumference of a circle}\\\\
C=2\pi r\qquad\qquad C=4\pi^2\implies 4\pi^2=2\pi r\implies \cfrac{4\pi^2}{2\pi }=r
\\\\\\
\boxed{2\pi =r}\\\\
-----------------------------\\\\
\textit{area of a circle}\\\\
A=\pi r^2\qquad \qquad A=\pi \left( \boxed{2\pi } \right)^2\implies A=\pi \cdot 4\pi^2\implies \boxed{A=4\pi^3}$

8 0

3 years ago

28 students in the class 75% pass how many students pass

SashulF [63]

Answer:

21 students pass

Step-by-step explanation:

Firstly, you can set up the problem into an equation where the variable X would equal the number of students passing. You put X over the total number of students in the class, turning it into a fraction, then set it equal to the fraction $\frac{75}{100}$ (which is 75% represented as a fraction).

$\frac{X}{28} = \frac{75}{100}$

The fraction $\frac{75}{100}$ can be simplified, because 75 and 100 are both multiples of 25, so after canceling out the 25s you would be left with $\frac{3}{4}$ .

$\frac{X}{28} = \frac{3}{4}$

Next, you use the process of cross multiplication which is essentially just multiplying the denominators of both fractions (which would be 28 and 4 in this case) to each side of the equation.

$\frac{X}{28} * 28 * 4 = \frac{3}{4} * 4 * 28$

The denominators cancel out leaving you with a simple equation to simplify.

$4* X = 3 * 28$

$4X = 84$

Finally, divide both sides by four in order to isolate the variable.

$\frac{4X}{4} = \frac{84}{4}$

X = 21.

5 0

3 years ago