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8_murik_8 [283]
2 years ago
5

Rule 1: Multiply by 2, then add one third starting from 0. Rule 2: Add one half, then multiply by 4 starting from 1. What is the

second ordered pair using the two sequences?

Mathematics
1 answer:
scoundrel [369]2 years ago
6 0

Answer: the "first" 1 is right

Step-by-step explanation:

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Approximately how many times greater is 2.3x10^-4 than 1.15x10^-8 ?
Minchanka [31]

Answer:

2.3 × 10^{-4} is 20,000 times greater than 1.15 × 10^{-8}

Step-by-step explanation:

Given as :

The first number= x = 2.3 × 10^{-4}

The second number= y = 1.15 × 10^{-8}

Let The first number is z times greater than second number

i.e x = z × y

Or, z = \dfrac{x}{y}

Or, z = \dfrac{2.3\times 10^{-4}}{1.15\times 10^{-8}}

Or, z = 2 × 10^{4}

∴  z = 20,000

So,The first number is 20,000 times greater than second number

Hence, 2.3 × 10^{-4} is 20,000 times greater than 1.15 × 10^{-8} . Answer

3 0
4 years ago
A zoo has 15 toucans and 60 parrots. What is the ratio of the number of toucans to the
ladessa [460]

Answer:

A, 1:4

Step-by-step explanation:

15:60 simplified:

3:12

1:4

8 0
3 years ago
Mary bought a smart phone and has $11.43 left. How much did Mary have before she bought the smart phone? Write an equation and s
TiliK225 [7]

Answer:

245.43

Step-by-step explanation:

6 0
3 years ago
This week, Beth made 10 more than twice the number of cookies she made last week, x.
elena-s [515]

so twice as much is 2 times x and she did 10 more than that quantity.

10 + 2x

5 0
4 years ago
How can (4x⁵/2x²)³ be solved in 2 different ways
Margaret [11]

We assume that we need to simplify the expression in two different ways.

Answer:

One way: Raise both, the numerator and denominator, to the third power, and then simplify the expression.

Second way: Simplify the terms inside parentheses, and then raise the result to the third power.

The result of both ways is the same: \\8x^{9}

Step-by-step explanation:

<em>One way</em>

Raise both, the numerator and denominator, to the third power, and then simplify the expression:

\\ (\frac{4x^{5}}{2x^{2}})^{3}

\\ (\frac{64x^{5*3}}{8x^{2*3}})

\\ (\frac{64x^{15}}{8x^{6}})

\\ \frac{64}{8}\frac{x^{15}}{x^{6}}

\\8x^{9}

This is the first simplification.

<em>Second way</em>

Simplify the terms inside parentheses, and then raise the result to the third power.

\\ (\frac{4x^{5}}{2x^{2}})^{3}

\\ (\frac{4}{2}*\frac{x^{5}}{x^{2}})^{3}

\\ (2*x^{5-2})^{3}

\\ (2*x^{3})^{3}

\\ (2^{3}*x^{3*3})

\\ (8*x^{9})

or \\ 8x^{9}.

3 0
3 years ago
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