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8_murik_8 [283]
2 years ago
5

Rule 1: Multiply by 2, then add one third starting from 0. Rule 2: Add one half, then multiply by 4 starting from 1. What is the

second ordered pair using the two sequences?

Mathematics
1 answer:
scoundrel [369]2 years ago
6 0

Answer: the "first" 1 is right

Step-by-step explanation:

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Find the value of y in the formula y=5a-3b c, if a=12,b=4,c=8
liberstina [14]
Y=5a-3b
Y=5(12)-3(4)
Y=60-12
Y=48

You don't have a sign between b and c in the equation, so I cannot help you with the last operation
8 0
3 years ago
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Solve each linear equation for x. (A) –12x + 9 = –15x x = (B) 4.5x + 11.5 = 8.5x + 3.5 x = (C) 23x – 9 = 13x x =
mojhsa [17]

Answer:

A. x = -3

B. x = 2

C. x = 9/10

Step-by-step explanation:

(A) –12x + 9 = –15x

Collect like terms

9 = -15x + 12x

9 = -3x

x = 9 / -3

x = -3

(B) 4.5x + 11.5 = 8.5x + 3.5

4.5x - 8.5x = 3.5 - 11.5

-4x = -8

x = -8 / -4

x = 2

(C) 23x – 9 = 13x

-9 = 13x - 23x

-9 = -10x

x = -9 / -10

x = 9/10

5 0
3 years ago
What is the product of the two integer values for $x$ for which $|x^2 - 16|$ is a prime number?
Nana76 [90]

Answer:

-9

Step-by-step explanation:

x² -16 = (x -4)(x +4)

This magnitude of this product can only be prime if one of the factors is ±1. Any other integer value of x will produce a composite number (or zero).

... For x-4 = ±1, x = 3 or 5

... For x+4 = ±1, x = -3 or -5

The values of x that are ±3 both give |x²-16| = 7, a prime.

The values of x that are ±5 both give |x²-16| = 9, not a prime.

The two values of x that are of interest are x=-3 and x=3. Their product is ...

... (-3)·(3) = -9

8 0
4 years ago
Someone please help me with an explanation please! Asap would be nice :)
Irina18 [472]

HOW TO DETERMINE SLOPE AND Y-INTERCEPT: Use the instructions below to answer this question.

EQUATION: y=\frac{-3}{4}x-3

-------------------------------------------------

<h2>INSTRUCTIONS:</h2>

FINDING THE Y-INTERCEPT:

Do this simply by finding the number your graph starts at on the Y-Axis (vertical line)! In this case, it's at -3!

FINDING SLOPE:

Remember that slope is rise over run (\frac{rise}{run})

RISE = How far the line goes <em>up </em>and <em>down</em>.

RUN = How far the line goes <em>left </em>or <em>right</em>.

HOW DO I FIND IT? All you have to do is count both rise and run from one point on the line to another! WARNING: The point must hit at a vertex, it cannot be counted if it is in the center of the box, or anywhere that does not touch the edge. I also suggest starting from the <u>Y-Intercept</u> and counting.

GOING LEFT OR DOWN: This is a positive number

GOING RIGHT OR UP: This is a negative number.

(You will see how this applies, below, yayyyy)

CALCULATING OUR NUMERATOR, AKA RISE:

Starting from the y, to get to the next point on the line, you can see we have to go down three. This means our numerator is -3!

CALCULATING OUR DENOMENATOR, AKA RUN:

Starting from where we just stopped, we must continue getting to the next point, and to do that, you can see we have to go to the right four! This means our denomenator is 4!

6 0
3 years ago
Can someone help me with this (will give brainliest)<br> please view the attached image
evablogger [386]

Answer:

4

Step-by-step explanation:

7 0
3 years ago
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