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Alex
2 years ago
5

What is the perimeter of the following figure?​

Mathematics
1 answer:
PSYCHO15rus [73]2 years ago
3 0

Answer:

13.4 x 2 = <em>26.8</em>

<em>12.5</em>

HYPOTENUSE:

10^2 + 12.5^2 = 256.25

Square root of 256.25 = around 16

which would equal 256

<em>16 </em>is your hypotenuse.

26.8 + 12.5 + 16 = 55.3 is your perimeter

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Given: ∆PQR, m∠R = 90° m∠PQR = 75° M ∈ PR , MP = 18 m∠MQR = 60° Find: RQ
tensa zangetsu [6.8K]

Answer:    RQ= 8.99 ( approx)

Step-by-step explanation:

Let MR= x

Since, In triangle, PRQ, tan 75°= \frac{18+x}{RQ}

⇒ RQ=  \frac{18+x}{tan 75^{\circ}}

Now, In triangle MRQ,

tan 60°= \frac{18+x}{RQ}

⇒ RQ=  \frac{x}{tan 60^{\circ}}

On equating both values of RQ,

\frac{18+x}{tan 75^{\circ}}=\frac{x}{tan 60^{\circ}}

⇒\frac{18+x}{x}=\frac{tan 75^{\circ}}{tan 60^{\circ}}

⇒\frac{18+x}{x}=\frac{tan 75^{\circ}}{tan 60^{\circ}}

⇒\frac{18+x}{x}=2.15470053838

⇒18=2.15470053838x-x

⇒x=15.5884572681≈15.60

Thus RQ=8.99999999999≈8.99


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