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madam [21]
2 years ago
13

PLEASE ANSWER ASAP!!! (full answers please, no begging for brainliest)

Mathematics
1 answer:
vfiekz [6]2 years ago
7 0

Answer: 5x + 2y ≤ $40; x,y ≥ 0

Step-by-step explanation:

5x + 2y ≤ $40

Technically, this is insufficient since it allows for purchases of negative amounts.

Really, it should be 5x + 2y ≤ $40 <u>and </u>x ≥ 0 <u>and</u> y ≥ 0. That is 3 inequalities.

No begging.  ;)

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54 percent of 24 is what
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12.96 is the answer.
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There were 60 ducks living in a pond. If the number living at the pond increased by 30%, how many ducks now live at the pond?
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Step-by-step explanation:

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The equation version:

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In the past decades there have been intensive antismoking campaigns sponsored by both federal and private agencies. In one study
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Answer:

z=\frac{0.384-0.362}{\sqrt{0.374(1-0.374)(\frac{1}{4276}+\frac{1}{3908})}}=2.055    

The p value can be calculated from the alternative hypothesis with this probability:

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And the best option for this case would be:

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Step-by-step explanation:

Information provided

X_{1}=1642 represent the number of smokers from the sample in 1995

X_{2}=1415 represent the number of smokers from the sample in 2010

n_{1}=4276 sample from 1995

n_{2}=3908 sample from 2010  

p_{1}=\frac{1642}{4276}=0.384 represent the proportion of smokers from the sample in 1995

p_{2}=\frac{1415}{3908}=0.362 represent the proportion of smokers from the sample in 2010

\hat p represent the pooled estimate of p

z would represent the statistic    

p_v represent the value for the pvalue

System of hypothesis

We want to test the equality of the proportion of smokers and the system of hypothesis are:    

Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}    

The statistic is given by:

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{1642+1415}{4276+3908}=0.374  

Replacing the info given we got:

z=\frac{0.384-0.362}{\sqrt{0.374(1-0.374)(\frac{1}{4276}+\frac{1}{3908})}}=2.055    

The p value can be calculated from the alternative hypothesis with this probability:

p_v =2*P(Z>2.055)=0.0399    

And the best option for this case would be:

C. between 0.01 and 0.05.

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