3 years ago

B) Solve x ^ 2 + 5x - 14 = 0

2 answers:

6 0

$x^2 +5x -14 =0\\\\\implies x^2 +7x -2x -14 =0\\\\\implies x(x+7) -2(x+7)=0\\\\\implies (x-2)(x+7) =0\\\\\implies x =2~~ \text{or}~~ x =-7$

Vinil7 [7]3 years ago

6 0

Answer:

x = -7 and x = 2

Step-by-step explanation:

x ^ 2 + 5x - 14 = 0 can be factored as follows: (x + 7)(x - 2). Note how 7x - 2x = 5x.

Setting each factor = to 0 and solving for x, we get x = -7 and x = 2.

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Hitman42 [59]

Answer:

Range D = {-7, 1, 9, 17}

Step-by-step explanation:

f(x) = 4x + 9

4(-4) + 9 = -7

4(-2) + 9 = 1

4(0) + 9 = 9

4(2) + 9 = 17

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3 years ago

Vedmedyk [2.9K]

Answer is 30.

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4 years ago

Marina CMI [18]

i think the correct answer is C

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3 years ago

mixer [17]

The rewritten form of the expression as a single logarithm is; log {(x+3)²(x-2)^5}/(x-7)³(x²).

<h3>What is the rewritten form of the expression?</h3>

The expression given in the task content can be rewritten as a single logarithm by virtue of the laws of logarithms as follows;

2log(x+3)-3log(x-7)+5log(x-2)-log(x^2)

= log(x+3)² - log(x-7)³ +log(x-2)^5-log(x^2)

= log {(x+3)²(x-2)^5}/(x-7)³(x²)