Answer:
See Explanation
Step-by-step explanation:
Given
Let
Strawberry
Banana
![S : B = 2 : 3](https://tex.z-dn.net/?f=S%20%3A%20B%20%3D%202%20%3A%203)
Solving (a):
Complete the table
The table, to be complete, is not given; so, I will generate one myself.
![\begin{array}{cccccc}S & {2} & {3} & {4} & {5} & {6} \ \\ {B} & {3} & {4.5} & {6} & {7.5} & {9} \ \end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bcccccc%7DS%20%26%20%7B2%7D%20%26%20%7B3%7D%20%26%20%7B4%7D%20%26%20%7B5%7D%20%26%20%7B6%7D%20%5C%20%5C%5C%20%7BB%7D%20%26%20%7B3%7D%20%26%20%7B4.5%7D%20%26%20%7B6%7D%20%26%20%7B7.5%7D%20%26%20%7B9%7D%20%5C%20%5Cend%7Barray%7D)
The table is generated as follows:
![S : B = 2 : 3](https://tex.z-dn.net/?f=S%20%3A%20B%20%3D%202%20%3A%203)
Multiply by 1.5
![S : B = 2 * 1.5 : 3 * 1.5](https://tex.z-dn.net/?f=S%20%3A%20B%20%3D%202%20%2A%201.5%20%3A%203%20%2A%201.5)
![S : B = 3 : 4.5](https://tex.z-dn.net/?f=S%20%3A%20B%20%3D%203%20%3A%204.5)
Multiply by 2
![S : B = 2*2 : 3*2](https://tex.z-dn.net/?f=S%20%3A%20B%20%3D%202%2A2%20%3A%203%2A2)
![S : B = 4 : 6](https://tex.z-dn.net/?f=S%20%3A%20B%20%3D%204%20%3A%206)
And so on....
<em>In summary, whatever factor is multiplied to S must be multiplied to B; in order to keep the ratio constant</em>
Solving (b): Why the amount are proportion
Because the ratio is constant and it remains unchanged all through.
<span>apply the Distributive Property and combine like terms in the expression
</span><span>
x + 3y − y + 3x + 2(2 + 4 + y)
= 4x + 2y+ 12 + 2y
= 4x + 4y + 12
answer
</span>B: 4x+4y+12
Answer: 2.3
Step-by-step explanation:
Calculator
Answer: 1,306,951,360
Step-by-step explanation:
Number of digits in Number system = 10
Number of letters in English Alphabet= 26
Number of ways to product code consists of a one digit number (including 0) followed by 5 not necessarily distinct (repetition is allowed) letters will be:-
(1)
Number of ways to product code consists of a two-digit number (including 0) followed by 5 not necessarily distinct (repetition is allowed) letters will be:-
(2)
Now, total product codes are possible: [Adding (1) and (2)]
![=26^5(10+10^2)\\\\=(11881376)(10+100)\\\\=11881376(110)\\\\=1306951360](https://tex.z-dn.net/?f=%3D26%5E5%2810%2B10%5E2%29%5C%5C%5C%5C%3D%2811881376%29%2810%2B100%29%5C%5C%5C%5C%3D11881376%28110%29%5C%5C%5C%5C%3D1306951360)
Hence, the number of product codes are possible = 1,306,951,360