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Bezzdna [24]
2 years ago
10

Ramon is a parking lot attendent. He estimates that 30% of the cars in the lot are sedans 10% are minivans and 20% are SUV's. He

designs a simulation.
what is the probabiloty that at least one of the next four cars that enter the lot is a sedan?

A.75%
B.70%
C.85%
D.80%

Mathematics
1 answer:
disa [49]2 years ago
5 0

Then the probability that at least one of the next four cars will be a sedan is 80%, the correct option is D.

<h3>How to find the probability that one of the next four cars that enter the lot is a sedan?</h3>

So we know that:

  • 30% of the cars are sedans.
  • 10% of the cars are minivans.
  • 20% of the cars are SUV's.

Now we have some simulation results, there are 20 outcomes on the simulation, and the numbers "0, 1, and 2" represent sedans.

Now we need to count how many of the 20 outcomes have one of these numbers, we can see that in 16 of the outcomes at least one of these 3 numbers appear.

Then the probability that at least one of the next four cars will be a sedan is 16 out of 20, or:

16/20  = 0.8

In percentage form, this is 0.8*100% = 80%, so the correct option is D.

If you want to learn more about probability.

brainly.com/question/25870256

#SPJ1

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The equation y= 1/2 x +4 is graphed below.which equation would intersect this line at (4, 6)?
Anton [14]

Answer:

we have the equation y = (1/2)*x + 4.

now, any equation that passes through the point (4, 6) will intersect this line, so if we have an equation f(x), we must see if:

f(4) = 6.

if f(4) = 6, then f(x) intersects the equation y = (1/2)*x + 4 in the point (4, 6).

If we want to construct f(x), an easy example can be:

f(x) = y = k*x.

such that:

6 = k*4

k = 6/4 = 3/2.

then the function

f(x) = y= (3/2)*x intersects the equation  y = (1/2)*x + 4 in the point (4, 6)

5 0
3 years ago
Using the letters in the word INNOVATIVE, find the number of permutations that can be formed using 4 letters at a time. Show you
lyudmila [28]

Answer:  1) 5040 and 2) 165

Step-by-step explanation:

1) Here total number of letters = 10

The number of permutations that can be formed using 4 letters at a time

= P (10, 4)

= 10_P_4

= \frac{10!}{(10-4)!}

=  \frac{10!}{6!}

= \frac{10\times 9\times 8\times 7\times 6!}{6!}

= 10 × 9 × 8 × 7

= 5040

2) Here the total number of machine = 11

The different combinations of machines can Geoff choose from to use

= 11_C_3

= \frac{11!}{(11-3)!3!}

= \frac{11!}{8!3!}

= \frac{11\times 10\times 9\times 8!}{8!\times 6}

= 11 × 5 × 3

= 165

5 0
3 years ago
Which change would make the statement below true?Circle the letter of the correct answer. 3.7 &lt; 3.56 A.put a 0 in the hundred
yKpoI14uk [10]
The answer's D, I think. Hope this helps.
3 0
3 years ago
0.058<br> −<br> 0.225<br> +<br> 6.4<br> 0.08
quester [9]

Answer:

0.345

Step-by-step explanation:

impretty sure thats right. but if im wrong im really sorry <333

4 0
3 years ago
19 = X -6
Readme [11.4K]
It pretty sure it would be X=25
3 0
3 years ago
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