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brilliants [131]
10 months ago
9

For a class trip, 114 students are put on buses. At this rate, how many students would be on eight buses? Show your work.

Mathematics
1 answer:
vredina [299]10 months ago
3 0

Answer:

Not really sure but 14.25 students seem to be the correct answer.

Step-by-step explanation:

114:8 = 14.25

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Jane is going to walk once around the edge of a rectangular park. The park is 300 yards long and 200 feet wide. How far will Jan
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Jane will walk 2200 feet 
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3 years ago
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At a new exhibit in the Museum of Science, people are asked to choose between 94 or 220 random draws from a machine. The machine
Tresset [83]

Answer:

0.0869 = 8.69% probability of getting more than 61% green balls.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

The machine is known to have 99 green balls and 78 red balls.

This means that p = \frac{99}{99+78} = 0.5593

Mean and standard deviation:

\mu = p = 0.5593

s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.5593*0.4407}{99+78}} = 0.0373

a. Calculate the probability of getting more than 61% green balls.

This is 1 subtracted by the pvalue of Z when X = 0.61. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.61 - 0.5593}{0.0373}

Z = 1.36

Z = 1.36 has a pvalue of 0.9131

1 - 0.9131 = 0.0869

0.0869 = 8.69% probability of getting more than 61% green balls.

8 0
2 years ago
2.54rounded to nearest tenth
Svetradugi [14.3K]
2.5 Is the answer. It is rounded to the nearest tenth.
6 0
3 years ago
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Can someone help me with this??
Umnica [9.8K]

Answer:

divide by 2

Step-by-step explanation:

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2 years ago
Determine whether the graphs of 7= 5x+9 and -y = -5x -9 are parallel, perpendicular, coincident, or none of these.
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Assuming your first equation is y = 5x+9, the equations describe lines that are coincident.

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Multiplying the second equation by -1, it becomes y = 5x+9, the same as the first equation.
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