What are the probabilities that the three subsystems, as well as the entire system, are operational?
1 answer:
Three subsystems are reliability-wise in series and make up a system. Subsystem 1 has a reliability of 99.5%, subsystem 2 has a reliability of 98.7% and subsystem 3 has a reliability of 97.3% for a mission of 100 hours.
We suppose that the system consists of one operating series subsystem, an identical stand-by subsystem, and a switch. Each subsystem consists of N components.
When the operating subsystem fails, the spare is put in motion by the switch immediately. The failed subsystem is restoring or changing the failed component. Because of the memoryless property of the exponential distribution of components lifetime, the renewal of a failed element means the renewal of the whole subsystem. We assume that there is a single repair facility. A renewal time is a random variable having distribution depending on a failed component. We suppose that the lengths of restoring periods of components are represented by identical copies of nonnegative random variables.
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Answer:
Time(t) = 11.61 hours (Rounded to two decimal place)
Step-by-step explanation:
Given: The antibiotic clarithromycin is eliminated from the body according to the formula:
......[1]
where;
A - Amount remaining in the body(in milligram)
t - time in hours after the drug reaches peak concentration.
Given: Amount of drug in the body is reduced to 100 milligrams.
then,
Substitute the value of A = 100 milligrams in [1] we get;
Divide both sides by 500 we get;
Simplify:
Taking logarithm both sides with base e, then we have;
[ Using
]
or
[using value of ]
then;
Simplify:
t ≈11.61 hours.
Therefore, the time 11.61 hours(Rounded two decimal place) will pass before the amount of drug in the body is reduced to 100 milligrams