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lubasha [3.4K]
3 years ago
12

What is the GCF of 10 and 21?

Mathematics
2 answers:
ki77a [65]3 years ago
7 0
I believe the answer is one.
mars1129 [50]3 years ago
3 0

Answer: 1

Step-by-step explanation:

The GCF of 10 and 21 is 1

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In the figure angle G measures 102° and angle B measures 30° what is the measurement of angle B
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On Martin's first stroke, his golf ball traveled 4/5 of the distance to the hole. On his second stroke, the ball traveled 79 met
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Answer:

0.395 kilometre

Step-by-step explanation:

Given:

On Martin's first stroke, his golf ball traveled 4/5 of the distance to the hole.

On his second stroke, the ball traveled 79 meters and went into the hole.

<u>Question asked:</u>

How many kilometres from the hole was Martin when he started?

<u>Solution:</u>

Let distance from Martin starting point to the hole in meters = x

On Martin's first stroke, ball traveled = \frac{4}{5} \ of \ total \ distance\ to\ the\ hole

                                                             =\frac{4}{5} \times x=\frac{4x}{5}

On his second stroke, the ball traveled and went to the hole = 79 meters

Total distance from starting point to the hole = Ball traveled from first stroke + Ball traveled from second stroke

x=\frac{4x}{5} +79\\ \\ Subtracting\ both\ sides\ by \ \frac{4x}{5}\\ \\ x- \frac{4x}{5}= \frac{4x}{5}- \frac{4x}{5}+79\\ \\ \frac{5x-4x}{5} =79\\ \\ By \ cross\ multiplication\\ \\ x=79\times5\\ \\ x=395\ meters

Now, convert it into kilometre:

1000 meter = 1 km

1 meter = \frac{1}{1000}

395 meters = \frac{1}{1000}\times395=0.395\ kilometre

Thus, there are 0.395 kilometre distance from Martin starting point to the hole.

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Tn = ar^(n-1); where a = 4, r = 5
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Explicit formular is Tn = 4/5 (5)^n

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