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2 years ago

What are common chemicals and hazardous materials often found in a kitchen environment?.

1 answer:

5 0

Common chemicals and hazardous materials that can be found in the kitchen include fuel gases, pesticides, sources of radon gas, and cleaning agents.

The kitchen is the main area of the house which is at the risk of having several accidents.

The carbon monoxide gas that is released from kitchen materials such as a gas stoves can be extremely harmful. A closed kitchen with no ventilation can cause carbon monoxide to level up, thus creating a hazardous atmosphere.

Certain gas appliances and furnaces in the kitchen are a source of radon gas. Radon compounds are hazardous as they can cause lung cancer.

Pesticides are poisonous chemicals that we often use in the kitchen to kill insects. Pesticides can be toxic to human health also.

Cleaning agents are present in almost every kitchen because these chemicals help in keeping the kitchen counters, stove, and other appliances clean. The cleaning agents have strong concentrations of ammonia and chlorine which are harmful to the skin.

Other hazardous materials in the kitchen environment include materials that can easily cause fire such as certain electrical appliances.

To learn more about hazardous materials, click here:

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Liquid sodium is being considered as an engine coolant. How many grams of liquid sodium (minimum) are needed to absorb 1.20 MJ 1

mars1129 [50]

Answer : The mass of liquid sodium needed are, $3.17\times 10^3g$

Explanation :

First we have to calculate the number of moles of liquid sodium.

$q=n\times c\times (\Delta T)$

where,

q = heat absorb = 1.20 MJ = 1.20 × 10⁶ J

n = number of moles of liquid sodium = ?

c = specific heat capacity = $30.8J/mol.K$

$\Delta T$ = change in temperature = $10.0^oC=273+10.0=283K$

Now put all the given values in the above formula, we get:

$1.20\times 10^6J=n\times 30.8J/mol.K\times 283K$

$n=137.7mol$

Now we have to calculate the mass of liquid sodium.

Molar mass of Na = 23 g/mol

$\text{Mass of Na}=\text{Moles of Na}\times \text{Molar mass of Na}$

$\text{Mass of Na}=137.7mol\times 23g/mol=3167.1g=3.17\times 10^3g$

Therefore, the mass of liquid sodium needed are, $3.17\times 10^3g$

3 0

4 years ago

Gaseous methane (CH₄) reacts with gaseous oxygen gas (O₂) to produce gaseous carbon dioxide (CO₂) and gaseous water (H₂O) If 0.3

AveGali [126]

Answer : The percent yield of $CO_2$ is, 68.4 %

Solution : Given,

Mass of $CH_4$ = 0.16 g

Mass of $O_2$ = 0.84 g

Molar mass of $CH_4$ = 16 g/mole

Molar mass of $O_2$ = 32 g/mole

Molar mass of $CO_2$ = 44 g/mole

First we have to calculate the moles of $CH_4$ and $O_2$ .

$\text{ Moles of }CH_4=\frac{\text{ Mass of }CH_4}{\text{ Molar mass of }CH_4}=\frac{0.16g}{16g/mole}=0.01moles$

$\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=\frac{0.84g}{32g/mole}=0.026moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$CH_4+2O_2\rightarrow CO_2+2H_2O$

From the balanced reaction we conclude that

As, 2 mole of $O_2$ react with 1 mole of $CH_4$

So, 0.026 moles of $O_2$ react with $\frac{0.026}{2}=0.013$ moles of $CH_4$

From this we conclude that, $CH_4$ is an excess reagent because the given moles are greater than the required moles and $O_2$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $CO_2$

From the reaction, we conclude that

As, 2 mole of $O_2$ react to give 1 mole of $CO_2$

So, 0.026 moles of $O_2$ react to give $\frac{0.026}{2}=0.013$ moles of $CO_2$

Now we have to calculate the mass of $CO_2$

$\text{ Mass of }CO_2=\text{ Moles of }CO_2\times \text{ Molar mass of }CO_2$

$\text{ Mass of }CO_2=(0.013moles)\times (44g/mole)=0.572g$

Theoretical yield of $CO_2$ = 0.572 g

Experimental yield of $CO_2$ = 0.391 g

Now we have to calculate the percent yield of $CO_2$

$\% \text{ yield of }CO_2=\frac{\text{ Experimental yield of }CO_2}{\text{ Theretical yield of }CO_2}\times 100$

$\% \text{ yield of }CO_2=\frac{0.391g}{0.572g}\times 100=68.4\%$

Therefore, the percent yield of $CO_2$ is, 68.4 %

6 0

3 years ago

Briefly explain why an unbalanced chemical equation cannot fully describe a reaction?

zubka84 [21]

From the conservation of mass, matter is not created nor destroyed. So ponder it this way, for example I put one piece of toast in a toaster, but when it is done I had two pieces, that makes no sense right? Same thing with a chemical reaction but in molecular terms, all things must stay constant. If you put a convinced amount you have to get that quantity back, not less or not more in broad terms.

5 0

3 years ago

What is hydrogen gas

UkoKoshka [18]

Hydrogen is the smallest elements , with one potron and one electron .it is highly abundant no has unique and important chemicals properties .

4 0

3 years ago

Read 2 more answers

When a scientific theory has been tested and proved by the scientific community, it becomes a law.

suter [353]

Answer:

False

Explanation:

Because laws and theories are developed for different purposes, laws never become theories, and theories do not become laws.

4 0

2 years ago