When molybdate (MoO3) and Zinc (Zn) are heated together they react in this equation:

Chemistry

1 answer:

schepotkina [342]3 years ago

5 0

Answer: The mole ratio of Zn to ZnO is 3: 3.

Explanation:

According to law of conservation of mass, mass can be neither be created nor be destroyed. The mass on reactant side must be equal to the mass on product side. Thus the atoms of each element on both side of the reaction must be same.

The balanced chemical reaction is:

$3Zn+2MoO_3\rightarrow Mo_2O_3+3ZnO$

Here 3 moles of Zn combine with 2 moles of $MoO_3$ to give 1 mole of $Mo_2O_3$ and 3 moles of $ZnO$ . Thus the mole ratio of Zn to ZnO is 3: 3.

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When the volume of a gas is

Montano1993 [528]

Answer:

$\boxed {\boxed {\sf 232.9 \textdegree C}}$

Explanation:

This question asks us to find the temperature change given a volume change. We will use Charles's Law, which states the volume of a gas is directly proportional to the temperature. The formula is:

$\frac {V_1}{T_1}= \frac{V_2}{T_2}$

The volume of the gas starts at 250 milliliters and the temperature is 137 °C.

$\frac{250 \ mL}{137 \textdegree C}= \frac{V_2}{T_2}$

The volume of the gas is increased to 425 milliliters, but the temperature is unknown.

$\frac{250 \ mL}{137 \textdegree C}= \frac{425 \ mL}{T_2}$

We are solving for the new temperature, so we must isolate the variable T₂. First, cross multiply. Multiply the first numerator and second denominator, then multiply the first denominator and second numerator.

$250 \ mL * T_2 = 137 \textdegree C * 425 \ mL$