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Mariulka [41]
3 years ago
9

A 475 ml sample of a gas was collected at room temperature of 23.5 °C and a pressure of

Chemistry
1 answer:
Molodets [167]3 years ago
3 0

Answer:

The volume when the conditions were altered is 0.5109 L or 510.9 mL

Explanation:

Using the general gas equation,

P1 V1 / T1 = P2 V2 / T2

where;

P1 = 756 mmHg

V1 = 475 ml = 0.475 L

T1 = 23.5°C = 23.5 + 273K = 275.5 K

P2 = 722 mm Hg

T2 = 10°C = 10 + 273 K = 283 K

V2 = ?

Rearranging to make V2 the subject of the formula, we obtain:

V2 = P1 V1 T2 / P2 T1

V2 = 756 * 0.475 * 283 / 722 * 275.5

V2 = 101, 625.3 / 198911

V2 = 0.5109 L or  510.9 mL

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If the metal in the ionic compound is a transition element (with variable charge metal ions), the ionic charge is written as a R
spayn [35]

Answer : The name of ionic compound is, Copper(II) fluoride.

Explanation :

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The nomenclature of ionic compounds is given by:

1. Positive ion is written first.

2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

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8 0
3 years ago
Do the following problem using significant figures.<br> 4.5 cm x 2000.0 cm x 4 cm =<br> I<br> cm^3
Anon25 [30]

Given :

Measurements 4.5\ cm\times 2000.0\ cm\times 4\ cm .

To Find :

The multiplication using significant figures .

Solution :

We know , the least number of significant figures in any number of the problem determines the number  of significant figures in the answer.

So , significant figure( S.F) in 4.5 cm is 2 .

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Now , multiplying them we will get :

M=4.5\times 2000.0\times 4 \ cm^3\\\\M=36000\ cm^3

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First we will write it in exponential 2 S.F form.

3.6\times 10^4 \ cm^3

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3 0
2 years ago
When 3.0g of magnesium is burnt in 2.00g of oxygen, 5.00g of magnesium oxide is produced. What mass of magnesium oxide will be f
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Answer: -

8.00 g

The law of conservation of mass

Explanation: -

When magnesium burns in air it combines with oxygen to form magnesium oxide.

The mass of the product is the mass of the magnesium oxide.

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