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Pavlova-9 [17]
2 years ago
14

For the function

tle="g(x)=\frac{-28}{2^{5x+5} }+7" alt="g(x)=\frac{-28}{2^{5x+5} }+7" align="absmiddle" class="latex-formula">
a) State the parent function in the form and express the function in the form

α ·(B^{k(x-d)})+c



b) State the transformations of g(x) in proper order from the parent function.



c) Express the function in the form y = ab^{x} +c



d) Determine the any asymptotes and state whether the function is an example of exponential growth or decay



e) Determine the domain and range of the function.



f) Calculate the x-intercept and y-intercept, then sketch the function.

Mathematics
1 answer:
Marina86 [1]2 years ago
7 0

The solutions to the questions are:

  • The equation of the function is g(x) = -7/8(2^-5x) + 7
  • The domain is -∝ < x < ∝ while the range is y < 7
  • The horizontal asymptote is y = 7 and the function is an example of exponential decay
  • The y-intercept is 49/8 while the x-intercept is -0.6

<h3>State the parent function in the form and express the function in the form</h3>

The function is an exponential function.

So, the parent function has the form

y = ab^x

Using the function in (a), the parent function is: y = -7/8 * 2^x and the form of the function is g(x) = -7/8(2^-5x) + 7

<h3>The transformation</h3>

First, the function is horizontally stretched by -5

This gives

g(x) = -7/8(2^-5x)

First, the function is shifted up by 7 units

This gives

g(x) = -7/8(2^-5x) + 7

<h3>Express the function in the form y = ab^x + c</h3>

The equation of the function is given as:

g(x) = -28/[2^(5x + 5)] + 7

Rewrite the equation as follows:

g(x) = -28/[2^(5x) * 2^5] + 7

Evaluate the exponent

g(x) = -28/[2^(5x) * 32] + 7

Divide

g(x) = -7/[2^(5x) * 8] + 7

Rewrite as:

g(x) = -7/[8 * 2^(5x)] + 7

Further, rewrite as:

g(x) = -7/8 * 2^(-5x) + 7

Rewrite properly as:

<h3>Determine any asymptotes and state whether the function is an example of exponential growth or decay</h3>

We have:

g(x) = -7/8 * 2^(-5x) + 7

Set the radical to 0

g(x) = 0 + 7

Evaluate

g(x) = 7

This represents the horizontal asymptote (it has no vertical asymptote)

Hence, the horizontal asymptote is y = 7 and the function is an example of exponential decay

<h3>Determine the domain and range of the function.</h3>

The function can take any input

So, the domain is -∝ < x < ∝

We have the horizontal asymptote to be

y = 7

The function cannot equal or exceed this value.

So, the range is y < 7

<h3>Calculate the x-intercept and y-intercept, then sketch the function.</h3>

Set x = 0

g(0) = -7/8 * 2^(-5 * 0) + 7

This gives

g(0) = -7/8 * 2^(0) + 7

Evaluate the exponent

g(0) = -7/8 + 7

Evaluate the sum

g(0) = 49/8

So, the y-intercept is 49/8

Set g(x) = 0

0 = -7/8 * 2^(-5x) + 7

This gives

-7 = -7/8 * 2^(-5x)

Divide by -7

1 = 1/8 * 2^(-5x)

Multiply by 8

8 = 2^(-5x)

Solve for x

x = -0.6

So, the x-intercept is -0.6

See attachment for the sketch

Read more about exponential functions at:

brainly.com/question/2456547

#SPJ1

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<h2>Hello!</h2>

The answer is:

When the domain is -3, the range is -13.

<h2>Why?</h2>

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Have a nice day!

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