3 years ago

What is the coefficient of the second term of the tribomial (3x+3)^2=9x^2+bc+9

Mathematics

1 answer:

FinnZ [79.3K]3 years ago

6 0

Answer:

Step-by-step explanation:

To find the second term of the coefficient, multiply out the left hand side of the equation.

$(3x+ 3)^2 = 9x^2 + bc + 9$

$(3x+3)(3x+3)\\9x^2 + 9x + 9x + 9\\9x^ 2+ 18x + 9$

The value of b is 18.

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