Answer:
y^5 ÷ y^3 * y^2 = y^4
Step-by-step explanation:
https://www.symbolab.com/solver/factor-calculator/Simplify%20y%5E%7B5%7D%5Cdiv%20y%5E%7B3%7D%C3%97y%5E%7B2%7D%20
(use that link if you want to see the work for yourself)
:)
<span>Solve for d.
5+d>5−d Subtract 5 from both sides of this inequality:
d>d There is no value for d that satisfies this inequality.
No value can be greater than itself.
</span><span>Solve for p.
2p+3>2(p−3) Multiply this out: 2p+3>2p-6
</span><span> Subtr 3 from both sides: 2p> 2p-9
This is equivalent to 2p+9>2p.
We could subtr. 2p from both sides: 0>-9.
0> -9 is always true. Thus, the given inequality has infinitely many solutions.
</span>
The solution to the given quadratic equation is;
x = -2 and x = 1/5
<h3>Roots of quadratic Equation </h3>
We are given the quadratic function;
(x + 2)(5x - 1) = 0
In quadratic functions, when it is expressed as;
(x + a)(x - b) = 0, what this means is that the factors of the quadratic equation or polynomial are; (x + a) and (x - b)
What that means is that the roots will be gotten from;
(x + a) = 0 and (x - b) = 0
Thus, applying the concept above on roots of a polynomial to our question, we have;
(x + 2) = 0 and 5x - 1 = 0
Solving them gives us;
x = -2 and x = 1/5
Read more on roots of quadratic equation at; brainly.com/question/8649555
Answer:
1. 30
2. 150
3. obtuse
4. acute
5. Adjacent
Step-by-step explanation:
Step-by-step explanation:
3x2 -5x+1=0
Quadratic eq ax2 +bx+c=0
Discriminant=b2 -4ac
=(-5)2 -4*3*1
=25-12
=13>0 so 2 solutions.
