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Allushta [10]
2 years ago
11

INDEPENDENT PRACTICE

Mathematics
1 answer:
nydimaria [60]2 years ago
8 0
1. False
2. True
3. True
4. True
5. False
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Contact [7]
When we bring 6y from right side to left side it’s sign get changed and 8y-6y=2y.
3 0
3 years ago
Identify the value that is equivalent to cos 27°.
vekshin1

Answer:

B. sin 63°

Step-by-step explanation:

cos 27°

cos (90° − 63°)

sin 63°

5 0
4 years ago
If you use the zeros , you can write the factored form of p(x) as p(x) = (x + 3/4)(x - 4/3) * (x - 2/5) than as p(x) = (4x + 3)(
Levart [38]

Answer: The standard form for the equation of an ellipse is:

(

x

−

h

)

2

a

2

+

(

y

−

k

)

2

b

2

=

1

The center is:

(

h

,

k

)

The vertices on the major axis are:

(

h

−

a

,

k

)

and

(

h

+

a

,

k

)

The vertices on the minor axis are:

(

h

,

k

−

b

)

and

(

h

,

k

+

b

)

The foci are:

(

h

−

√

a

2

−

b

2

,

k

)

and

(

h

+

√

a

2

−

b

2

,

k

)

To put the given equation in standard form, change the + 2 to - -2 and write the denominators as squares:

(

x

−

3

)

2

4

2

+

(

y

−

−

2

)

2

3

2

=

1

The center is:

(

3

,

−

2

)

The vertices on the major axis are:

(

−

1

,

−

2

)

and

(

7

,

−

2

)

The vertices on the minor axis are:

(

3

,

−

5

)

and

(

3

,

1

)

Evaluate:

√

a

2

−

b

2

=

√

4

2

−

3

2

=

√

16

−

9

=

√

5

The foci are:

(

3

−

√

5

,

−

2

)

and

(

3

+

√

5

,

−

2

)

6 0
3 years ago
Instruction: use the ratio of a 30-60-90 triangle to solve for the variables. Leave your answers as radicals in simplest form.u=
almond37 [142]

Let's start by identify a 30-60-90 triangle

If we compare those two traingles we can stablish the following relation:

\begin{gathered} a\sqrt[]{3}=6\sqrt[]{3} \\  \end{gathered}

Therefore, a=6

u is the opposite side to the 90° angle, therefore

\begin{gathered} u=2a \\ u=2\cdot6 \\ u=12 \end{gathered}

on the other hand, v is the opposite side to the 30° angles, so

\begin{gathered} v=a \\ v=6 \end{gathered}

6 0
2 years ago
A circle with a radius of 3cm sits inside of a circle with a radius of 5cm. What is the area of the Shaded Region? Round your an
tresset_1 [31]

Answer:

A=50.27\ cm^2

Step-by-step explanation:

<u><em>The complete question is</em></u>

A circle with a radius of 3 cm sits inside of a circle with a radius of 5 cm. What is the area of the Shaded Region?

The shaded region is the area outside the smaller circle and inside the larger circle

we know that

The area of the shaded region is equal to subtract the area of the smaller circle from the area of the larger circle

Remember that

The area of the circle is equal to

A=\pi r^{2}

so

The area of the shaded region is

A=\pi [r_1^2-r_2^2]

where

r_1=5\ cm

r_2=3\ cm

substitute

A=\pi [5^2-3^2]

A=\pi [16]

A=16\pi\ cm^2

assume

\pi =3.1416

substitute

A=16(3.1416)=50.27\ cm^2

4 0
3 years ago
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