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SOVA2 [1]
2 years ago
7

To determine how much fluid she should be replenishing with, Kimmy weighs herself before and after a 2-hour run and finds she lo

ses 3 pounds during the run. If approximately 2 cups of fluid weighs 1 pound, and she should replace her lost fluid pound-for-pound, how many fluid ounces total should Kimmy replenish with during and after her run
Mathematics
1 answer:
leva [86]2 years ago
4 0
She lost 3 lbs
2 cups of fluid for each 1 lb
3 lbs x 2 cups of fluid = 6 cups of fluid
3 x 2 = 6
6 cups of fluid
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Angelina_Jolie [31]
<h3>The final amount is $ 6881.71</h3>

<em><u>Solution:</u></em>

<em><u>The formula for compound interest, including principal sum, is:</u></em>

A = p(1 + \frac{r}{n})^{nt}

Where,

A = the future value of the investment

P = the principal investment amount\

r = the annual interest rate in decimal

n = the number of times that interest is compounded per unit t

t = the time the money is invested

From given,

p = 4000

t = 5

r = 11 \% = \frac{11}{100} = 0.11

n = 4 ( compounded quarterly )

<em><u>Substituting the values in formula,</u></em>

A = 4000(1 + \frac{0.11}{4})^{4 \times 5}\\\\ A = 4000( 1.0275)^{20}\\\\A = 4000 \times 1.720428\\\\A = 6881.7137 \approx 6881.71

Thus the final amount is $ 6881.71

5 0
3 years ago
You want to have 80000 college fund in 12 years. How much will you have to deposit now under the scenario below. Assume that you
stealth61 [152]

9514 1404 393

Answer:

  $32,528.58

Step-by-step explanation:

For simplicity, we'll assume each year has 365 days.

The future value A of principal amount P at rate r compounded daily for t years is ...

  A = P(1 +r/365)^(365t))

We want P when A = 80,000, r = 0.075, and t = 12.

  P = A/(1 +r/365)^(365t)

  P = $80000/(1+0.075/365)^(365·12) ≈ $32,528.58

You will have to deposit about $32,528.58.

3 0
3 years ago
What changes would you make in your description of point, line, and plane?
weeeeeb [17]

Answer:

Here's a quick sketch of how to calculate the distance from a point P=(x1,y1,z1)

P

=

(

x

1

,

y

1

,

z

1

)

to a plane determined by normal vector N=(A,B,C)

N

=

(

A

,

B

,

C

)

and point Q=(x0,y0,z0)

Q

=

(

x

0

,

y

0

,

z

0

)

. The equation for the plane determined by N

N

and Q

Q

is A(x−x0)+B(y−y0)+C(z−z0)=0

A

(

x

−

x

0

)

+

B

(

y

−

y

0

)

+

C

(

z

−

z

0

)

=

0

, which we could write as Ax+By+Cz+D=0

A

x

+

B

y

+

C

z

+

D

=

0

, where D=−Ax0−By0−Cz0

D

=

−

A

x

0

−

B

y

0

−

C

z

0

.

This applet demonstrates the setup of the problem and the method we will use to derive a formula for the distance from the plane to the point P

P

.

Step-by-step explanation:

5 0
3 years ago
If the radioactive half-life of a substance is 20 days, and there are 5 grams of it initially. When will the amount left be 2 gr
Kobotan [32]

Answer: 26.4\ \text{days}

Step-by-step explanation:

Given

Half life of radioactive substance is T_{\frac{1}{2}}=20\ \text{days}

Initial amount A_o=2\ \text{days}

Amount left at any time is given by

\Rightarrow A=A_o2^{\dfrac{-t}{T_{\frac{1}{2}}}}\\\\\Rightarrow 2=52^{\dfrac{-t}{20}}\\\\\Rightarrow 0.4=2^{\dfrac{-t}{20}}\\\\\Rightarrow 2^{\dfrac{t}{20}}=2.5\\\\\Rightarrow \dfrac{t}{20}\ln 2=\ln (2.5)\\\\\Rightarrow t=\dfrac{20\ln (2.5)}{\ln 2}\\\\\Rightarrow t=26.4\ \text{days}

It takes 26.4 days to reach 2 gm.

7 0
3 years ago
2^(n-1) = 256 ? Please give me the answer​
klemol [59]

Answer:

n = 9

Step-by-step explanation:

Note that

256 = 2^{8}, thus

2^{n-1} = 2^{8}

Since the bases on both sides are equal (2) equate the exponents

n - 1 = 8 ( add 1 to both sides )

n = 9

7 0
3 years ago
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