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pochemuha
2 years ago
6

rapid prototyping could be an advantageous methodology for developing innovative computer-based instruction. Software engineers

have been successful in designing applications by using rapid prototyping. so it also
Computers and Technology
1 answer:
frosja888 [35]2 years ago
8 0

The option that is true for the Student Version above is option d:  This is not plagiarism.

<h3>What is plagiarism?</h3>

This is known to be the act of copying other people's work and then taking it as your own.

When you look at the student work, you will see some measures od differences. Hence, The option that is true for the Student Version above is option d:  This is not plagiarism.

Learn more about prototyping  from

brainly.com/question/14743515
#SPJ1

See  full question below

Original Source Material

There is a design methodology called rapid prototyping, which has been used successfully in software engineering. Given similarities between software design and instructional design, we argue that rapid prototyping is a viable method for instructional design, especially for computer-based instruction.

Student Version

Rapid prototyping could be an advantageous methodology for developing innovative computer-based instruction. Software engineers have been successful in designing applications by using rapid prototyping. So it also could be an efficient way to do instructional design.

Which of the following is true for the Student Version above?

a. Word-for-Word plagiarism

b. Paraphrasing plagiarism

c. This is not plagiarism

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______was developed as an interim management protocol with OSI as the ultimate network management protocol.
RSB [31]

Answer:

Simple Network Management Protocol

Explanation:

Simple Network Management Protocol otherwise referred to as SNMP is a form of computer protocol that is mainly used in obtaining and regulating information relating to connected gadgets. It is practically based on the internet and was originally planned as an interim protocol.

Hence, it can be concluded that the Simple Network Management Protocol was developed as an interim management protocol with OSI as the ultimate network management protocol.

4 0
3 years ago
You were discussing software piracy with a friend and were surprised to learn how software piracy can impact your life every day
Vika [28.1K]
Those who use pirate software:
<span>1)Increase the chances that the software will not function correctly or will fail completely
2)Forfeit access to customer support, upgrades, technical documentation, training, and bug fixes
3)Have no warranty to protect themselves
4)Increase their risk of exposure to a debilitating virus that can destroy valuable data
5)May find that the software is actually an outdated version, a beta (test) version, or a nonfunctioning copy
6)Are subject to significant fines for copyright infringement</span>
5 0
3 years ago
Implement the function couple, which takes in two lists and returns a list that contains lists with i-th elements of two sequenc
In-s [12.5K]

Answer:

couple.py

def couple(s1,s2):

  newlist = []

  for i in range(len(s1)):

      newlist.append([s1[i],s2[i]])

  return newlist

s1=[1,2,3]

s2=[4,5,6]

print(couple(s1,s2))

enum.py

def couple(s1,s2):

  newlist = []

  for i in range(len(s1)):

      newlist.append([s1[i],s2[i]])

  return newlist

def enumerate(s,start=0):

  number_Array=[ i for i in range(start,start+len(s))]

  return couple(number_Array,s)

s=[6,1,'a']

print(enumerate(s))

print(enumerate('five',5))

Explanation:

7 0
3 years ago
1. find the network address for 172.22.49.252/17
mariarad [96]

Answer:

1. The network address for 172.22.49.252/17 is 172.22.0.0/17.

2. The last valid assignable host address of 172.22.4.129/26 is 172.22.4.190.

3. The first and last host address of 192.167.25.25/16 is 192.167.0.1 and 192.167.255.254.

4. The broadcast address of 10.75.96.0/20 is 10.75.111.255

Explanation:

Subnetting in networking is the process of managing the use of host addresses and subnet masks of a network IP address. For example, the IP address "172.22.49.252/17" is a class B address that receives an extra bit from the third octet which changes its subnet-mask from "255.255.0.0" to "255.255.128.0". with this, only 32766 IP addresses are used, with the network address of "172.22.0.0/17".

7 0
3 years ago
A 4-way set associative cache has 64 blocks of 16 words. How many bits are there in the ""tag"" field of the 15-bit address for
Tanya [424]

Answer:

3 bits

Explanation:

Given a 4- way set associative cache that has 64 blocks of 16 words.

Therefore, the number of sets cache has:

\frac{64}{4} = 16

Now,

Cache data size is 16kB

The number of cache blocks can be calculated as:

16kB/16 = 1024 bytes/16 byte\times 16 = 256 cache blocks

Now,

Total sets = \frac{cache blocks}{associative sets}

Total sets = \frac{256}{4} = 64

Now,

2^{n} = 64

n = 6

For 15 bit address for the architecture, the bits in tag field is given by:

15 - (6 + 6) = 3 bits

Thus the tag field will have 3 bits

6 0
3 years ago
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