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Ad libitum [116K]
2 years ago
8

Bill uses mirrors to augment the “laser experience” at a laser show. At one show he places three mirrors, A, B, C, in a right tr

iangular form. If the distance between A and B is 24m more than the distance between A and C, and the distance between B and C is 24m less than the distance between A and C, what is the distance between mirror A and mirror C?
Mathematics
1 answer:
USPshnik [31]2 years ago
5 0

The distance between mirror A and mirror C is,: AC = 96, BC=72, AB =120.

<h3>Distance</h3>

AC = x

BC = x- 24

AB = x + 24

<h3>Pythagorean theorem</h3>

AB2  = AC2 +   BC2

or ( x + 24 )²= x² + ( x - 24 )²

x² + 48 x + 576 = x² + x² - 48x + 576

96 x = x²

x (96 - x ) = 0

x= 96

Hence,

AC = 96

BC = 96-24=72

AB = 96+24=120

Therefore the distance between mirror A and mirror C is,: AC = 96, BC=72, AB =120.

Learn more about distance here:brainly.com/question/23848540

#SPJ1

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