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marishachu [46]
2 years ago
15

If x=3 than 5x+2= HELPPPPPPPPP

Mathematics
2 answers:
Andrej [43]2 years ago
8 0

Answer:

17

Step-by-step explanation:

5x+2

(5*3)+2

15+2

17

Sphinxa [80]2 years ago
4 0
5(3) + 2 =

15 + 2 =

17
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Help plz I will give brainliest
HACTEHA [7]

Answer:

i think that it is C

Step-by-step explanation:

if im incorrect i apologize

5 0
3 years ago
Mason, a hardwood flooring installer, needs to calculate the amount of hardwood flooring needed to cover a floor that's 33⁄4 yar
Aleksandr-060686 [28]

Answer:

20 5/8 yd^2

Step-by-step explanation:

width = 3 3/4 yd

length = 5 1/2 yd

First change both measurements to fractions.

3 3/4 = 3 + 3/4 = 12/4 + 3/4 = 15/4

5 1/2 = 5 + 1/2 = 10/2 + 1/2 = 11/2

area = length * width

area = 15/4 yd * 11/2 yd

area = (15 * 11)/(4 * 2) yd^2

area = 165/8 yd^2

165/8 = 20 remainder 5

area = 20 5/8 yd^2

3 0
3 years ago
f(x) = 32g(x) = V48xFind (f.g)(x). Assume x20.O A. (f.g)(x) = 72.O B. (f.g)(x) = V51xO c. (f.g)(x) = 12/xO D. (fºg)(x) = 12xSUBM
QveST [7]

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data

f(x) = √3x

g(x) = √48x

(f . g)(x) = ?

Step 02:

(f . g)(x) :

\text{          (f.g)(x) = }\sqrt[]{3(\sqrt[]{48x)}}(f.g)(x)\text{ = }\sqrt[]{3(48x)^{\frac{1}{2}}}\text{ }

(f.g)(x) = 12 √ x

The answer is:

(f.g)(x) = 12 √ x

3 0
1 year ago
During halftime of a basketball ​game, a sling shot launches​ T-shirts at the crowd. A​ T-shirt is launched from a height of 4 f
Sonbull [250]

Answer:

(a) The time the T-shirt takes to maximum height is 2 seconds

(b) The maximum height is 68 ft

(c) The range of the function that models the height of the T-shirt over time given above is 4 + 64\cdot t - 16 \cdot  t^{2}

Step-by-step explanation:

Here, we note that the general equation representing the height of the T-shirt as a function of time is

h = h_1 + u\cdot t - \frac{1}{2} \cdot g  \cdot  t^{2}

Where:

h = Height reached by T-shirt

t = Time of flight

u = Initial velocity = 64 ft/s

g = Acceleration due to gravity (negative because upward against gravity) = 32 ft/s²

h₁ = Initial height of T-shirt = 4 ft

(a) The maximum height can be found from the time to maximum height given as

v = u - gt

Where:

u = Initial velocity = 64 ft/s

v = Final upward velocity at maximum height = 0 m/s

g = 32 ft/s²

Therefore,

0 = 64 - 32·t

32·t = 64 and

t = 64/32 = 2 seconds

(b) Therefore, maximum height is then

h = 4 + 64\times 2 - \frac{1}{2} \times 32  \times  2^{2}

∴ h = 68 ft

The T-shirt is then caught 41 ft above the court on its way down

(c) The range of the function that models the height of the T-shirt over time given above is derived as

h = h_1 + u\cdot t - \frac{1}{2} \cdot g  \cdot  t^{2}

With u = 64 ft/s

g = 32 ft/s² and

h₁ = 4 ft

The equation becomes

h =4 + 64\cdot t - \frac{1}{2} \times 32  \cdot  t^{2} = 4 + 64\cdot t - 16 \cdot  t^{2}.

6 0
3 years ago
I'm not really good at these types of questions would really appreciate some help.
Lunna [17]

Answer:

Thanks!

Step-by-step explanation:

The falling leaves and the draining of the pool signal an end and parallel the end of the illusion and the end of Gatsby's life.

7 0
3 years ago
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