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Vaselesa [24]
3 years ago
9

If I know A B C equals d e f can you stay B C equals ef​

Mathematics
1 answer:
algol133 years ago
5 0
If ABC and DEF are triangles, then yes you can!
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The value of y varies directly with x. When y = 7, x = 2. what is the value of x when y is 21?
mrs_skeptik [129]
Y=kx
7=k(2)
k=7/2

y=kx
21=7/2(x)
x=6
8 0
3 years ago
Which expression is not equivalent to the other three?
Effectus [21]

Answer:

c or d

Step-by-step explanation:

tell me which one it is

7 0
2 years ago
List the part ail products of 42×28
skelet666 [1.2K]
U can use the area model by doing 20*40=800 ,8*40=320 ,20*2=40 ,8*2=16
4 0
3 years ago
A carnival game gives players a 25% chance of winning every time it has played a player plays the game four times let XP the num
allsm [11]

Answer:

0.6836 = 68.36% probability that the player will win at least once.

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the player wins, or the player loses. The probability of winning a game is independent of any other game, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

25% chance of winning

This means that p = 0.25

Plays the game four times

This means that n = 4

What is the probability that the player will win at least once?

This is:

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{4,0}.(0.25)^{0}.(0.75)^{4} = 0.3164

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.3164 = 0.6836

0.6836 = 68.36% probability that the player will win at least once.

8 0
3 years ago
Find the solutions of the form x=a,y=0and x=0 ,y=b for the following equations: 2x+5y=10 and 2x+3y=6. is there any common soluti
Arlecino [84]

Answer:

 x=0 and y=2

Step-by-step explanation:

We have been given system of equations:

2x+5y=10     (1)

And 2x+3y=6     (2)

Subtract equation (2) from(1) we get:

2y=4

y=2

Now, substitute y=2 in equation(2) we get:

2x+3(2)=6

2x+6=6

2x=0

x=0

Hence, x=0 and y=2


8 0
3 years ago
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