There are the combinations that result in a total less than 7 and at least one die showing a 3:
[3, 3] [3,2] [2,1] [1,3] [2,3]
The probability of each of these is 1/6 * 1/6 = 1/36
There is a little ambiguity here about whether or not we should count [3,3] as the problem says "and one die shows a 3." Does this mean that only one die shows a 3 or at least one die shows a 3? Assuming the latter, the total probability is the sum of the individual probabilities:
1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 5/36
Therefore, the required probability is: 5/36
Answer: 266
Step-by-step explanation: This is a ratio problem. If there are 14 chocolates with nuts out of every 32 chocolates, you can use this as a ratio and set it up as a proportion.
(1) 14 chocolates w/ nuts / 32 chocolates = n chocolates / 608 chocolates
(2) Solve for n: 8,512 = 32n; n = 266
Answer:
The answer would be "no because boys on the basketball team are likely to be taller than other boys at the school"
Step-by-step explanation:
Hope this helps:)...if not then sorry for wasting your time and may God bless you:)
Answer:
The expression that is equivalent to -6x+9y would be -3(2x-3y)
