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Paul [167]
3 years ago
15

Can y’all tell me the answer of these 4 questions

Mathematics
2 answers:
vaieri [72.5K]3 years ago
8 0

Answer:#1. No

#2. Second option

#3. No

#4. 76%

Step-by-step explanation:

None is needed.

11Alexandr11 [23.1K]3 years ago
4 0

Answer:

Yes

2n+4

No

76 percent

Step-by-step explanation:

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A. 1/5 fish

We know that 2/5 of Mike's fish are clownfish. Therefore, 3/5 are not clownish as 5/5 – 2/5 = 3/5. Also, if you look at the model, there are five pieces. If we assume that model represents the whole of Mike's fish and you take away two pieces, you are left with 3/5. So we know that the remaining fish is 3/5

Next, we know that of these 3/5 fish, 1/3 is damselfish, so we need to find 1/3 of 3/5. To do this, we must multiply 1/3 by 3/5 as "of" means multiply in Math.

So: 1/3 • 3/5 = 1 • 3/3 • 5 = 3/15       3 ÷ 3 = 1 and 15 ÷ 3 = 5    3/15 = 1/5

1/5 of Mike's fish are damsel fish


B. 2/5 fish

Now we know that 1/5 of Mike's fish is damselfish, and 2/5 is clownfish. To find the fraction of his fish that are neither, therefore, we must subtract their sum from the whole.

First, we add 1/5 and 2/5 together. Adding the numerators, 1 and 2, we get 1/5 + 2/5 = 3/5

Next, we subtract: 5/5 – 3/5 = 2/5, so 2/5 of his fish are neither clownfish or damselfish

And if you look at the model again, you can see that if you cross out 1 piece for the damselfish, and 2 pieces for the clownfish, you are left with 2/5

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Scilla [17]
Try making a substitution:
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