Answer:10 over 13 x
Step-by-step explanation: convert the decimal number into a fraction 800-5x divided by 13 over 2
to divided by a fraction , multiply by the reciprocal of that fraction 800-5x x2 over 13
factor out 5 from the expression 5(160-x x2over 13) use the commutative property to reorder the terms 5(160-2over 13x) factor out 1 over 13 from the expression 5x 1 over 13x(2080-2x)factor out 2 from the expression 5x 1 over13 x2(1040-x)use the commutative property to recorder the terms 5*2x 1 over 13x (1040x) calculate the product 10 over 13x(1040-x) solution 10 over 13x (1040-x)
for simplify expression: covert the decimal number into a fraction 800-5x divided by 13 over 2 to divide by a fraction , multiply by the reciprocal of that fraction 800-5x x2 over 13 calculate the product 800- 10 over 13x
solution: 800-10 over 13x so your answer would still be
Answer:
of, relating to, or according to the methods or principles of geometry
increasing in a geometric progression.
the study of properties of given elements that remain invariant under specified transformations
explanation:
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Answer:
600 numbers
Step-by-step explanation:
For six-digit numbers, we need to use all digits 8,0,1,3,7,5 each once.
However, 0 cannot be used as the first digit, because it would make a 5-digit number.
Therefore
there are 5 choices for the first digit (exclude 0)
there are 5 choices for the first digit (include 0)
there are 4 choices for the first digit
there are 3 choices for the first digit
there are 2 choices for the first digit
there are 1 choices for the first digit
for a total of 5*5*4*3*2*1 = 600 numbers
-2x+4y=4 Equation 1
x-2y=6 Equation 2
Solving by substitution method.
Isolate x from equation 2.
x=2y+6
Substitute value of x in equation 1
-2(2y+6)+4y=4
-4y-12+4y=4
-12=4
-16=0
Which is false.
Answer: No solution
The missing value in the logarithm are as follows:
- log₃ 7 - log₃ 2 = log₃ (7 / 2)
- log₉ 7 + log₉ 4 = log₉ 28
- log₆ 1 / 81 =
- - 4 log₆ 3
<h3>How to solve logarithm?</h3>
Using logarithm rule,
logₐ b - logₐ c = logₐ (b / c)
logₐ b + logₐ c = logₐ (b × c)
Therefore,
log₃ 7 - log₃ 2 = log₃ (7 / 2)
log₉ 7 + log₉ 4 = log₉ (7 × 4) = log₉ 28
log₆ 1 / 81 = log₆ 81⁻¹ = log₆ 3⁻⁴ = - 4 log₆ 3
learn more on logarithm here: brainly.com/question/24515212
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