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2 years ago

Distrubutive property 1. 54+27=9 (_+_)

Mathematics

2 answers:

Rudiy272 years ago

8 0

Hey there!

54 + 27 = 81

9(6 + 3)

= 9(6) + 9(3)

= 9 + 9 + 9 + 9 + 9 + 9 + 9 + 9 + 9

= 18 + 18 + 18 + 18 + 9

= 36 + 36 + 9

= 72 + 9

= 81

Thus, the equation answwr is: 81

Therefore, the overall answer is:

9(6 + 3)

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Anarel [89]2 years ago

3 0

Answer:

9(6+3) = 54+27

Step-by-step explanation:

dunno how to explain but hope the answer helps

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Write the equation in slope intercept form. what are the slope and y intercept -5x-12y=11

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The slope is -5/12

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3 years ago

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astra-53 [7]

<h2>Answer:</h2>

Option: C is the correct answer.

C. $a_n=a_{n-1}-3\ ;\ a_1=2$

<h2>Step-by-step explanation:</h2>

The sequence is given by the explicit formula as:

$a_n=5-3n$

where $a_n$ is the nth term of the sequence.

Also, the first term of the sequence is: $a_1$

i.e.

$a_1=5-3\times 1\\\\i.e.\\\\a_1=5-3\\\\i.e.\\\\a_1=2$

Also,

$a_n=5-3n\\\\i.e.\\\\a_n=5-3n+3-3\\\\i.e.\\\\a_n=5-3(n-1)-3\\\\i.e.\\\\a_n=a_{n-1}-3$

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Option: C

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3 years ago

Please Help ASAP!!!<br> 25 POINTS !!

alina1380 [7]

Answer:

Step-by-step explanation:

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3 years ago

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Which of the following is an extraneous solution of (45-3x)^1/2=x-9?

Iteru [2.4K]

Answer:

C. x =3

Step-by-step explanation:

Extraneous solution is that root of a transformed equation that doesn't satisfy the equation in it's original form because it was excluded from the domain of the original equation.

Let's solve the equation first

$\sqrt{45-3x} = x-9\\Taking\ square\ on\ both\ sides\\{(\sqrt{45-3x})}^2 = {(x-9)}^2\\45-3x = x^2-18x+81\\0 = x^2-18x+81-45+3x\\x^2-15x+36 = 0\\x^2-12x-3x+36 = 0\\x(x-12)-3(x-12) = 0\\(x-3)(x-12)\\x-3 = 0\\=> x =3\\x-12 = 0\\x = 12\\We\ will\ check\ the\ solutions\ one\ by\ one\\So,\\for\ x=3\\\sqrt{45-3(3)} = 3-9\\\sqrt{45-9} = -6\\\sqrt{36}= -6\\6\neq -6\\For x=12\\\sqrt{45-3(12)} = 12-9\\\sqrt{45-36} = 6\\\sqrt{36}= 6\\6=6$

Hence, we can conclude that x=3 is an extraneous solution of the equation ..

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Answer:

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Step-by-step explanation:

Hope it helps ;)

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