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skad [1K]
2 years ago
6

Quadrilateral ABCD is dilated by a scale factor of 2 centered around (2,2).

Mathematics
1 answer:
ANEK [815]2 years ago
6 0

Answer:

B’D’ will run through (2,2) and will be longer than BD

Step-by-step explanation:

B'D' will be twice as long as BD and run through (2, 2).

You might be interested in
If y=kx, where k is a constant, and y=24 when x=6, what is the value of y when x=5?A. 6B. 15C. 20D. 23
Marizza181 [45]

First, we will find the value of k

We can do this by sybstituting y=24, x=6 in;

y=kx and then solve for k

24= k(6)

divide both-side of the equation by 6

24/6 = k

4 = k

k=4

Then when x = 5, we will substitute x=5 and k=4 in; y=kx and then solve for y

y= (4)(5)

y = 20

7 0
1 year ago
What is the equation of the line that is parallel to y = 3x - 1 and goes through the point (0, 9)?
Mrac [35]

Answer:

Step-by-step explanation:

y - 9 = 3(x - 0)

y - 9 = 3x - 0

y = 3x + 9

8 0
2 years ago
2. In what ratio does the point (5, 4) divide the given line joining the points (2,1) and (7,6)​
Darya [45]

Answer:

3/2

Step-by-step explanation:

Let it be

C (5;4) , A (2;1) ; B(7;6)

Suppose that C divide the line AB in ratio m/n from point A (AC is m, CB is n)

Use the formula xc=(m*xb+n*xa)/ (m+n)

5=(m*7+2n)/(m+n)

5m+5n= 7m+2n

2m=3n

m/n=3/2

5 0
2 years ago
Ramona is counting the posts between mile markers on the highway. In 1 mile, she counts 33 posts if the posts are evenly spaced,
goldfiish [28.3K]

Answer:

it would be 5 divided by 280 and then that would tell u the answer 56 so it would be 56 feet. I hope this worked have a nice day.

Step-by-step explanation:

3 0
2 years ago
the arlington drama club is selling tickets to an upcoming play. They can sell at most 250 tickets. The adult tickets for $15 ea
allochka39001 [22]

Number of adult tickets = 75

Number of student tickets = 175

Solution:

Let x represents the number of adult tickets and

y represents the number of student tickets.

Total number of tickets sold = 250

⇒ x + y = 250 – – – – (1)

Cost of adult ticket = $15

Cost of student ticket = $5

Total cost of collection = $2000

15x + 5y = 2000 – – – – (2)

Multiply equation (1) by 5

⇒ (1) × 5  5x + 5y = 1250 – – – – (3)

Subtract equation (3) from equation (2), we get

15x + 5y – 5x – 5y = 2000 – 1250

⇒ 10x = 750

⇒ x = 75

Substitute x = 75 in equation (1), we get

⇒ 75 + y = 250

⇒ y = 250 – 75

⇒ y = 175

Number of adult tickets = 75

Number of student tickets = 175

6 0
3 years ago
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