Answer:
see the attachment
Step-by-step explanation:
The function can be ...
D(t) = A +Bcos(C(t-p))
where A is the average depth (55+12)/2 = 33.5 cm,
B is the peak deviation from average, 55 -33.5 = 21.5 cm,
C is the horizontal scale factor (2π/T) = (2π/3) for a period (T) of 3 seconds,
and p is the phase offset, given as 1.1 seconds.
The function is ...
D(t) = 33.5 +21.5cos(2π/3·(t -1.1))
Answer:
Probability of obtaining no more than two defective tubes = 0.816
Step-by-step explanation:
The Probability of obtaining no more than two defective tubes in a randomly selected sample of 15 tubes is obtained using the binomial distribution formula: nCr × p^r × q^(n -r).
Where n is number of samples;
r is maximum number of defective tubes, r ≤ 2;
p is probability of defective tubes = 10% or 0.1
q is probability of non-defective tubes, q = 1 - p
Further explanations and calculations are given in the attachment below:
