Answer:
C)
region C
Step-by-step explanation:
We have to use what is called the zero-interval test [test point] in order to figure out which portion of the graph these inequalities share:

0 ≤ 2 ☑ [We shade the portion of the graph that CONTAIN THE ORIGIN, which is the bottom portion.]

0 ≥ −3 ☑ [We shade the portion of the graph that CONTAINS THE ORIGIN, which is the left side.]
So, now that we got that all cleared up, we can tell that both graphs share a region where the ORIGIN IS VISIBLE. Therefore region C matches the above inequalities.
I am joyous to assist you anytime.
Whats the question? we cant help you if you dont give us the question.
Answer:
800 m
Step-by-step explanation:
Hello from MrBillDoesMath!
Answer:
33769/181
Discussion:
Each term contains "x" so factoring it out gives
x( 1/4 + 1/14 + 1/17) = 71 (*)
Use common factor (17*14*4 = 952) as the denominator to combine terms:
1/4 = (17*14)/ 952 = 238/952
1/14 = (17*4)/952 = 68/952
1/17 = (14*4)/952 = 56/952
so 1/4 + 1/14 + 1/17 = (238 + 68 + 56)/ 952 = 362/952 = 181/476
Substituting in (*) gives
x ( 181/476) = 71 => multiply both sides by 476/181
x = (71 * 476)/181 => 71* 476 =33769
x = 33769/181
Thank you,
MrB
Answer:
the bottom right
Step-by-step explanation: